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nikklg [1K]
3 years ago
7

Write an equation using at least 4 numbers

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0
Mine is 5x + 17 hope that it is usefull
rosijanka [135]3 years ago
6 0
A good one could be 4x5-4 divide by 2
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Twice y is at most 29
ArbitrLikvidat [17]

Answer:

2t=29

Step-by-step explanation:

the phrase is at most means we set the constant 29 less than or equal to the term 2t using the (<=) operator

4 0
3 years ago
Wht about this? i dont know how to do it :')
bagirrra123 [75]

multiply the pro #s by the con ones

5 0
3 years ago
Solve for the value of x.
Nikitich [7]

Answer:

mRS. lOPEZ HAS TWO KINDS OF FLOWERS IN HER GARDEN. THE RATIO OF LILLIES TO DAISIES IN THE GARDEN 5:3

Step-by-step explanation:

HELP ME

7 0
3 years ago
At a carry-out pizza restaurant, an order of 3 slices of pizza, 4 breadsticks, and 2 juice drinks costs $13.35. A second order o
BartSMP [9]

Answer: Pizza = $2.95, Breadstick = $0.50, Juice = $1.25

<u>Step-by-step explanation:</u>

Let P represent the cost of a slice of pizza

and B represent the cost of breadstick

and J represent the cost of a juice drink.

EQ1: 3P + 4B + 2J = 13.35

EQ2: 5P + 2B + 3J = 19.50

EQ3: 4B + J = P + 0.30     -->     P - 4B - J = -0.30

Let's eliminate B from EQ1 and EQ2 to form EQ4:

3P + 4B + 2J = 13.35   →  1(3P + 4B + 2J = 13.35)   →   3P + 4B + 2J =  13.35

5P + 2B + 3J = 19.50  → -2(5P + 2B + 3J = 19.50)  →  <u>-10P -  4B -  6J</u> = <u>-39.00</u>

                                                                        EQ4:     -7P          -4J    = -25.65

And eliminate B from EQ1 and EQ3 to form EQ5:

               3P + 4B + 2J = 13.35  

             <u>    P -  4B  - J </u> =<u> -0.30</u>

EQ5:       4P           + J  = 13.05    

Now, eliminate J from EQ4 and EQ5 to solve for P:

-7P  - 4J = -25.65  →    1(-7P  - 4J = -25.65)   →   -7P  - 4J = -25.65

 4P  +  J = 13.05   →    4(4P  +   J =  13.05)    →  <u>  16P  +4J </u>=  <u>52.20</u>

                                                                             9P          = 26.55

                                                                           <u>÷9   </u>           <u>÷9     </u>

                                                                                    P = 2.95

Plug in P = 2.95 into EQ4 or EQ5 to solve for J:

EQ5: 4P + J = 13.05

        4(2.95) + J = 13.05

        11.80 + J = 13.05

                   J = 1.25

Plug in P = 2.95 and J = 1.25 into either EQ1 or EQ2 or EQ3 to solve for B:

EQ3: 4B + J = P + 0.30

        4B + 1.25 = 2.95 + 0.30

        4B + 1.25 = 3.25

                   4B = 2.00

                     B = 0.50

Check (since we used EQ3 to find B, use either EQ1 or EQ2):

EQ2: 5P + 2B + 3J = 19.50

       5(2.95) + 2(0.50) + 3(1.25) = 19.50

       14.75 + 1.00 + 3.75 = 19.50

                            19.50 = 19.50     \checkmark

6 0
3 years ago
Enter the amplitude of the function f(x). f(x)=3cos(2x)+5
Molodets [167]

Hello from MrBillDoesMath!

Answer:

3

Discussion:

Amplitude applies to trig functions such as sin, cos. The amplitude of f(x) is 3 and its vertical shift is 5

Thank you,

MrB

8 0
4 years ago
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