Answer: Add 5 to both sides
What is the first step needed to solve 4 over 7 the whole multiplied by x minus 5 equal negative 13?
Answer- Add 5 to both sides
(4/7)x - 5 = -13
• As mentioned above, first step would be,
adding 5 to both sides
=> (4/7)x - 5 + 5 = -13 + 5
=> (4/7)x = -8
• Now, transporting 7 from L.H.S. to R.H.S
=> 4x = -8 × 7
=> 4x = -56
• Now in the same way, transporting 4 from L.H.S. to R.H.S
=> x = (-56/4)
=> x = -14
• And in this way, or taking<u> (Add 5 to both sides)</u> as our first step, we find that the value of x is -14.
<u>∴ </u><u> </u><u>x = -14</u>
Hope it helps.
Answer:
0.25
Step-by-step explanation:
Answer:
This a circle centered at the point 
, and of radius "3" as it is shown in the attached image.
Step-by-step explanation:
Recall that the standard formula for a circle of radius "R", and centered at the point 
is given by:
Therefore, in our case, by looking at the standard equation they give us, we extract the following info:
1) 
since the radius must be a positive number and (
) is not a viable answer.
2) 
for ( 
) to equal 
3) 
for ( 
) to equal 
Therefore, we are in the presence of a circle centered at the point , and of radius "3". That is what we draw as seen in the attached image.
Answer:
Final answer is ![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
.
Step-by-step explanation:
Given problem is ![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
.
Now we need to simplify this problem.
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
Hence final answer is .
