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Marysya12 [62]
3 years ago
9

Read the paragraph.

English
2 answers:
Snowcat [4.5K]3 years ago
5 0

Answer:

eagerly

Explanation:

eagerly matches the rest of the paragraph's tone

jonny [76]3 years ago
4 0

Answer:

The best and correct answer would be eagerly

You might be interested in
B
Marysya12 [62]

Answer:

(1) has thrilled

(2) have inspired

(3) have stopped

(4) have intruded

(5) have lost

(6) has been lost

(7) has prompted

(8) wanted

6 0
3 years ago
4. Supply the past continuous of the verbs in parentheses.
adell [148]
A) helped
B) ran
C) looked
D) drove
8 0
3 years ago
Read the following sentence from the passage.
zhenek [66]

Answer:

the answer is CCCCCC

Explanation:

3 0
3 years ago
Read 2 more answers
I know this is a lot, but i'll give you brainliest if you help :)
melisa1 [442]

1. Look, I want brainliest. I really do. But if you have the book you could screenshot or show me, that would be a great help.

2.  This screenshot is too small. I can barely read it anyway

3 0
3 years ago
How many different 55​-letter words can be made a. if the first letter must be Upper K or Upper XK or X and no letter may be​ re
Vika [28.1K]

Answer:

(a) The number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is 607,200.

(b) The number of 5-letter word that can be formed (with repetition) such that the first letter is K or X is 913,952.

(c) The number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is 24,288.

Explanation:

In this case we need to form a 5 letter word.

(a)

The condition applied is: 1st letter is K or X.

The word will of the form: K _ _ _ _ or X _ _ _ _

There are 2 ways to fill the first space, i.e. with either K or X.

Repetition is not allowed.

The remaining 4 spaces can be filled in (25 × 24 × 23 × 22) ways.

Then the total number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is:

Number of 5-letter word = 2 × 25 × 24 × 23 × 22 = 607200

Thus, the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is 607,200.

(b)

In case the repetition are allowed the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X is:

Number of 5-letter word = 2 × 26 × 26 × 26 × 26 = 913952

Thus, the number of 5-letter word that can be formed (with repetition) such that the first letter is K or X is 913,952.

(c)

The condition applied is: 1st letter is K or X and the last letter is J.

The word will of the form: K _ _ _ J or X _ _ _ J

There are 2 ways to fill the first space, i.e. with either K or X, and the last with J.

Repetition is not allowed.

The remaining 3 spaces can be filled in (24 × 23 × 22) ways.

Then the total number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is:

Number of 5-letter word = 2 × 24 × 23 × 22 = 24288

Thus, the number of 5-letter word that can be formed (without repetition) such that the first letter is K or X and the last is J is 24,288.

3 0
3 years ago
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