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Evgesh-ka [11]
2 years ago
7

A birdbath is filled to the top. On Day 1, the volume of water in the bowl decreases by 7/8 cup. On Day 2, the volume in the bow

l decreases by 3/4 cup. What number represents the total change in the volume of water in the bowl after two days? Write your answer as a mixed number.
Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0

Answer:

-1 5/8

Step-by-step explanation:

Let the total amount in the bowl be x;

If on Day 1, the volume of water in the bowl decreases by 7/8 cup, the remaining water will be;

x - 7/8

If on day 2, the volume in the bowl decreases by 3/4 cup, the remaining volume of water after the second day will be;

= x - 7/8 - 3/4

= x - (7-2(3))/8

= x - (7+6)/8

= x - 13/8

This shows that the total change after the two days is -13/8

As a mixed fraction;

-13/8 = -1 5/8

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LenaWriter [7]

Answer:

1203.6 ---- the six is recurring ( .666666...)

Step-by-step explanation:

volume of hemisphere= \frac{2}{3} x 3.14 x r^3

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1. Volume of hemisphere= 2/3 x 3.14 x 5^3 = 261.6 recurring

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1 year ago
Is 50 to 32 and 10 to 8 proportional
mestny [16]

Answer:

No

Step-by-step explanation:

10 x 5 = 50

8 x 5 = 40

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3 years ago
The incubation time for hummingbird eggs is approximately normal and has a mean of 16 days and standard deviation of 2 days. Let
Veseljchak [2.6K]

Answer:

0.5328 = 53.28% probability that the length of hatching times is between 15 and 18 days.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 16 days and standard deviation of 2 days.

This means that \mu = 16, \sigma = 2

Probability that the length of hatching times is between 15 and 18 days.

This is the p-value of Z when X = 18 subtracted by the p-value of Z when X = 15. So

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 16}{2}

Z = 1

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X = 15

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16}{2}

Z = -0.5

Z = -0.5 has a p-value of 0.3085

0.8413 - 0.3085 = 0.5328

0.5328 = 53.28% probability that the length of hatching times is between 15 and 18 days.

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2 years ago
Can you graph x+y=2 x-y=4??
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Answer:

Here, especially for you.

5 0
3 years ago
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