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3 years ago

In a group of 50 children, 11 cannot swim. What percentage can swim?

Mathematics

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

78% of the children can swim

Step-by-step explanation:

There are 50 children, 11 of them cannot swim. The fraction of children that cannot swim is 11/50. We have to change that into a percentage.

11/50 x 2 will equal our percentage

11 x 2 = 22

50 x 2 = 100

22/100 or 22%

We have the percentage of the children who cannot swim, now we have to find the percentage of children who can swim.

100% - 22% = 78%

I Hope That This Helps! :)

You might be interested in

Eurostar is a high-speed railway service connecting

erma4kov [3.2K]

Answer:

Step-by-step explanation:

This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).

350000 passengers

(350000 passengers) * 1

(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)

[note: passengers and carriages cancel. Leaving only trains]

(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]

729.1667 trains [oh, but don’t just round this number either up or down]

729 full trains can carry 729*32*15 = 349920 passengers

730 full trains can carry 730*32*15 = 350400 passengers

Now, we can say that 730 trains are adequate to carry 350000 passengers.

6 0

3 years ago

John wants to send a letter to Peter, who lives on Tesla

blondinia [14]

Answer:

The minimum number of letters John has to send to be sure that Peter receives his letter is 127 letters

Step-by-step explanation:

The four digit numbers that are multiples of 5 and 7 with the last digit = 0 is found as follows

Since the last digit of the house number = 10, then the house number is divisible by 10 which also meets the condition that the house number is divisible by 5

We have the four digit numbers from 1000 to 9999

Hence the numbers divisible by both 7 and 10 are from (1000/70 (Which is 14 + 2/7) - 2/7)×70 + 70 = 1050 to (9999/70 (Which is 142 + 59/70)- 59/70)×70= 9940

Which gives 142 - 15 = 127 numbers which are four digit number multiples of 5 and 7 with the last digit = 0

Hence the minimum number of letters John has to send to be sure that Peter receives his letter = 127 letters.

5 0

3 years ago

There are 2.54 centimeters to 1 inch. how many centimeters are in 15 inches

Rainbow [258]

15*2.54 = 38.1

Cause theres 15 of them

8 0

3 years ago

Read 2 more answers

Select the correct answer. Which number has a terminating decimal expansion? A. 2/7 B.√12 C. 5/8 D. 2/11

quester [9]

Answer:

Option C is correct option.

Step-by-step explanation:

We need to determine which number has a terminating decimal expansion.

Terminating decimal

A decimal number that contains a finite number of digits after the decimal point is called terminating decimal .

for example 0.123 is terminating decimal as it has finite number of digits after decimal point.

Now, we will look at each option to find the terminating decimal

A. 2/7

Converting in decimal form: 0.28571....

As it doesn't contain finite numbers after decimal point, so 2/7 is not terminating decimal.

B.√12

Converting in decimal form: 3.46410....

As it doesn't contain finite numbers after decimal point, so √12 is not terminating decimal.

C. 5/8

Converting in decimal form: 0.625

As it contain finite numbers after decimal point, so 5/8 is terminating decimal.

D. 2/11

Converting in decimal form: 0.18181....

As it doesn't contain finite numbers after decimal point, so 2/11 is not terminating decimal.

Therefore, Option C is correct option.

4 0

3 years ago

For each explicitly-defined sequence below, write the first few terms. Then use the terms to write a recursive equation.

julia-pushkina [17]

Answer:

Step-by-step explanation:

Problem A

t(1) = 2(1) + 5

t(2) = 2*2 + 5 = 9

t(3) = 2*3 + 5 = 11

t(4) = 2*4 + 5 = 13

So this is the explicit result. Now try it recursively.

t_3 = t_2 + 2

t_3 = 9 + 2

t_3 = 11 which is just what it should do.

t_n = t_(n - 1) + 2

Problem B

t(1) = 3 * 1/2

t(1) = 3/2

t(2) = 3*(1/2)^2

t(2) = 3 * 1/4

t(2) = 3/4

t(3) = 3*(1/2)^3

t(3) = 3 * 1/8

t(3) = 3/8

t(4) = 3 (1/2)^4

t(4) = 3 (1/16)

t(4) = 3/16

So in general

t_n = t_n-1 * 1/2

For example t(5)

t_5 = t_4 * 1/2

t_5 = 3 /16 * 1/2 = 3/32

6 0

3 years ago