-3x^2-2x (+-)6=0
ax^2+bx+c
a=-3
b=-2
c= either positive or negative 6 (there is no plus or minus in your question.)
What are the answer choices? It might help.
Answer:
yup it's d
Step-by-step explanation:
Answer:
The numbers are x = 3 and y = 1. Therefore the value of xy is 3.
Step-by-step explanation:
In order to calculate the numbers we will simplify the equation, this is done bellow:
2*x + x(2^2) + (y*2^3) + (y*2^4) = 42
2*x + 4*x + 8*y + 16*y = 42
6*x + 24*y = 42
We can divide the whole equation by 6, so we have:
x + 4*y = 7
The only possible combination of numbers that are positive and integers that will make the equation valid is x = 3 and y = 1. Therefore he value of xy is 3.
Answer:
b,f is right
Step-by-step explanation:
