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Aleksandr [31]
3 years ago
12

Given the equation 1/4y+3/4=8, what number

Mathematics
1 answer:
const2013 [10]3 years ago
3 0

Answer:

#fddddffdddfloodsuuf

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Temka [501]

Answer:  8\sqrt{2}

==========================================================

Work Shown:

Focus entirely on triangle ABD (or on triangle BCD; both are identical)

The two legs of this triangle are AB = 8 and AD = 8. The hypotenuse is unknown, so we'll say BD = x.

Apply the pythagorean theorem.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\x = \sqrt{8^2 + 8^2}\\\\x = \sqrt{2*8^2}\\\\x = \sqrt{8^2*2}\\\\x = \sqrt{8^2}*\sqrt{2}\\\\x = 8\sqrt{2}\\\\

So that's why the diagonal BD is exactly 8\sqrt{2}\\\\ units long

Side note: 8\sqrt{2} \approx 11.3137

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