Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
Answer:
11
Step-by-step explanation:
duh add 1 and 1 merge it together to get 11
Answer:
1,3,4
Step-by-step explanation:
The answer is A my dude, this is easy math lol
The x coordinates are 3 and -5. They add to 3+(-5) = -2
Cut this in half to get -2/2 = -1
The x coordinate of the midpoint is x = -1
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The y coordinates are 2 and 5. They add to 2+5 = 7.
Then we cut this in half to get 7/2 = 3.5
The y coordinate of the midpoint is y = 3.5
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Overall, the midpoint is (-1, 3.5)
<h3>Answer: (-1, 3.5) which is the same as (-1, 7/2)</h3>
