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alekssr [168]
3 years ago
7

Through: (3, 5) parallel to y=3x-1

Mathematics
2 answers:
aliina [53]3 years ago
4 0
Y = 3x-4 yuh yuh yuh yuh
marysya [2.9K]3 years ago
3 0

Answer:  y = 3x - 4  will be the parallel line to the line  y= 3x -1

Step-by-step explanation:

Parallel lines have the same slope but different y intercepts, so using the equation given , use the formula y=mx +b  where m is the slope and b is the

y - intercept ,and input the x and y coordinate to solve for b. Input the same slope into the formula because they will have the same slope.

 5= 3(3) + b  

5 =  9  + b

-9    -9

b = -4    

Since the y intercept is negative 4, the equation will be  y = 3x -4

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Step-by-step explanation:

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
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Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

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