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3 years ago

Please help with explanation if anyone can

Mathematics

1 answer:

diamong [38]3 years ago

6 0

Answer:

3.7 million

Step-by-step explanation:

14,100,000 = 3,000,000 + 3p

3p = 11,100,000

p = 11,100,000 / 3

p = 3,700,000

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Write a polynomial function of the least degree that has roots of 3 and (4 + i).

polet [3.4K]

Answer:

x³ - 11x² + 41x - 51

Step-by-step explanation:

The least number of degree is 3 and the third root should be (4 - i) to make polynomial rational.

<u>The polynomial is:</u>

(x - 3)(x - (4 + i))(x - (4 + i)) =
(x - 3)(x² -x(4 + i + 4 - i) + (4 + i)(4 - i)) =
(x - 3)(x² - 8x + 16 - (-1)) =
(x - 3)(x² - 8x + 17) =
x³ - 8x² + 17x - 3x² + 24x - 51 =
x³ - 11x² + 41x - 51

4 0

3 years ago

Please help needed asap this is due in minutes.

goldenfox [79]

I’m pretty sure the second questions answer is y=3x+2

3 0

3 years ago

Read 2 more answers

What is the angle e in the triangle below? (Hint: Use an inverse trigonometric

yuradex [85]

Answer:

Step-by-step explanation:

sin θ=3/8

θ=sin ^{-1}(3/8)

≈22.02 °

5 0

3 years ago

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What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

3 years ago

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PLS HELP ME ASAP WITH 1, 2, 5, 6, 11, and 12 PLS!!

melamori03 [73]

1-

number 2) is correct

2- 3) is true

11) Jacob is not correct. because 6radical 5 is irrational

12) radical 20 is an irrational number but

so a+b is irrational

but
$\sqrt{225} = 15 \\ it \: is \: rational$

so b+c is rational

good luck

8 0

3 years ago