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ehidna [41]
2 years ago
6

Answer this ASAP the last question that due 5 minutes

Mathematics
2 answers:
kati45 [8]2 years ago
6 0

Answer:

C

Step-by-step explanation:

If you graph the points, count boxes from the orgin (0,0).

You will have to go 3 to the right (on x), and up 6 (on y).

Tema [17]2 years ago
4 0
I think it is C, sorry if i’m wrong aahh
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Find the earnings for giving a haircut to m men and w women. Justify your answer
Ratling [72]
Woman and men would be the same price, if the haircuts are very popular, each gender got the same haircut, then they also would be the same price, it is mostly about the prices, interestingness, and popularity or each barbershop, go by your nearest barbershop and see what prices they have. :))
3 0
3 years ago
The cost, C dollars, of hiring a taxi is given by the formula C=2.00+320n, where n is the number of tenths of a mile driven. Wha
Ainat [17]

Answer:

$14.80

Step-by-step explanation:

I'm assuming you meant to put 3.20 since $320 a mile would be ridiculous.

C(n)=2.00+3.20n

If n = 4 miles we have:

C(4)=2+3.20(4)

C(4)=2+12.80

C(4)=14.80

So the cost of the taxi is $14.80.

8 0
2 years ago
A shipment of 50,000 transistors arrives at a manufacturing plant. The quality control engineer at the plant obtains a random sa
Aleks04 [339]

Step-by-step explanation:

remember, the number of possible combinations to pick m out of n elements is C(n, m) = n!/(m! × (n-m)!)

50,000 transistors.

4% are defective, that means 4/100 = 1/25 of the whole.

so, the probability for one picked transistor to be defective is 1/25.

and the probability for it to work properly is then 1-1/25 = 24/25.

now, 500 picks are done.

to accept the shipment, 9 or less of these 500 picks must be defective.

the probability is then the sum of the probabilities to get

0 defective = (24/25)⁵⁰⁰

1 defective = (24/25)⁴⁹⁹×1/25 × C(500, 1)

= 24⁴⁹⁹/25⁵⁰⁰ × 500

2 defective = (24/25)⁴⁹⁸×1/25² × C(500, 2)

= 24⁴⁹⁸/25⁵⁰⁰ × 250×499

3 defective = 24⁴⁹⁷/25⁵⁰⁰ × C(500, 3) =

= 24⁴⁹⁷/25⁵⁰⁰ × 250×499×166

...

9 defective = 24⁴⁹¹/25⁵⁰⁰ × C(500, 9) =

= 24⁴⁹¹/25⁵⁰⁰ × 500×499×498×497×496×495×494×493×492×491 /

9×8×7×6×5×4×3×2 =

= 24⁴⁹¹/25⁵⁰⁰ × 50×499×166×71×31×55×494×493×41×491

best to use Excel or another form of spreadsheet to calculate all this and add it all up :

the probability that the engineer will accept the shipment is

0.004376634...

which makes sense, when you think about it, because 10 defect units in the 500 is only 2%. and since the whole shipment contains 4% defect units, it is highly unlikely that the random sample of 500 will pick so overwhelmingly the good pieces.

is the acceptance policy good ?

that completely depends on the circumstances.

what was the requirement about max. faulty rate in the first place ? if it was 2%, then the engineer's approach is basically sound.

it then further depends what are the costs resulting from a faulty unit ? that depends again on when the defect is usually found (still in manufacturing, or already out there at the customer site, or somewhere in between) and how critical the product containing such transistors is. e.g. recalls for products are extremely costly, while simply sorting the bad transistors out during the manufacturing process can be rather cheap. if there is a reliable and quick process to do so.

so, depending on repair, outage and even penalty costs it might be even advisable to have a harder limit during the sample test.

in other words - it depends on experience and the found distribution/probability curve, standard deviation, costs involved and other factors to define the best criteria for the sample test.

3 0
1 year ago
I need help with this question. Please thanks
NNADVOKAT [17]

Answer:

all you need to do is to multiple

5 0
3 years ago
Read 2 more answers
When taking skinfold measurement readings only one attempt per site is necessary for an accurate reading.a. Trueb. False
Eva8 [605]

Answer: False

Step-by-step explanation: Skinfold measurements is one of the oldest ways of measuring a person's fat percentage,it's usually taken in specific areas of the body where there are Skinfolds,while taking this measurements it is expected that the person taking it does the average of 2or more repeated measurements in order to ensure that the actual thickness of that area of the body is correctly entered.

It is specifically taken from the right side of the body,where the person pinches out the Skinfolds away from the body by attaching a caliper ,this is to ensure that only the fatty laters are considered, it is mainly presented in percentage.

3 0
2 years ago
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