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3 years ago

Find the slope of the line passing through the points (-4, -3) and (8, -9).

Mathematics

2 answers:

deff fn [24]3 years ago

7 0

Answer: -6/12

Step-by-step explanation:

Use slope formula m= y2-y1/x2-x1, which would be -9-(-3)/8-(-4) = -6/12; X1= -4, Y1= -3, X2=8, Y2=-9

lana [24]3 years ago

5 0

Answer:

-1/2

Step-by-step explanation:

-9--3=-6

8--4= 12

-6/12

-1/2

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Solve absolute value equations and show work step by step please due tomorrow

Sergio039 [100]

Answer:

12) x = 10 or x = -10

13) b = 3 or b = -3.

14) r = 6 or r = -2

15) n = 0 or -2

Step-by-step explanation:

12) Given, 4|x| + 3 = 43

Now, for x ≥ 0, |x| = x and for x < 0, |x| = -x

So, for x ≥ 0, the equation becomes 4x + 3 = 43

⇒ 4x = 40

⇒ x = 10

Again, for x < 0, we have - 4x + 3 = 43

⇒ - 4x = 40

⇒ x = - 10

Therefore, the solution of the equation is x = 10 or x = -10. (Answer)

13) Given, 3|b| + 5 = 14

Now, for b ≥ 0, |b| = b and for b < 0, |b| = -b

So, for b ≥ 0, the equation becomes 3b + 5 = 14

⇒ 3b = 9

⇒ b = 3

Again, for b < 0, we have - 3b + 5 = 14

⇒ - 3b = 9

⇒ b = - 3

Therefore, the solution of the equation is b = 3 or b = -3. (Answer)

14) 9|2r - 4| + 1 = 73

Now, for 2r - 4 ≥0 i.e. r ≥ 2, then

9(2r - 4) + 1 = 73

⇒ 2r - 4 = 8

⇒ 2r = 12

⇒ r = 6

Again, for (2r - 4) < 0 i.e. r < 2, then

9(4 - 2r) + 1 = 73

⇒ 4 - 2r = 8

⇒ 2r = - 4

⇒ r = -2

Hence, the solutions are r = 6 and r = -2 (Answer)

15) For, 10n + 10 ≥ 0 i.e. n ≥ -1, then

1 + 4(10n + 10) = 41

⇒ 10n + 10 =10

⇒ 10n = 0

⇒ n = 0

Again, for 10n + 10 < 0 i.e. n < -1, then

1 - 4(10n + 10) = 41

⇒ 10n + 10 = - 10

⇒ 10n = -20

⇒ n = -2

Hence, the solution is n = 0 or -2 (Answer)

4 0

4 years ago

Math simplify (7a+5b-2c) + (5a+7b) + (2a-7c) + (2a-5b+3c) algebra

Alekssandra [29.7K]

Answer:

$-10a^2+25ab-15ac+12a+12b-2c$

Step-by-step explanation:

$(7a+5b-2c)+(5a+7b)+(2a-7c)+(2a-5b+3c)$

Distribute:

$=7a+5b-2c+5a+7b+(2a)(2a)+(2a)(-5)+(2a)(3c)+(-7a)(2a)+(-7a)(-5b)+(-7a)(3c)$

$=7a+5b-2c+5a+7b+4a^2-10ab+6ac-10a^2+35ab-21ac$

Combine all like terms:

$=(4a^2-14a^2)+(-10ab+35ab)+(6ac-21ac)+(7a+5a)+(5b+7b)+(-2c)$

$=-10a^2+25ab-15ac+12a+12b-2c$

6 0

3 years ago

Marianne can say hello in more than 7

Lady_Fox [76]

Answer:

Number line A.

Step-by-step explanation:

The first number line A, represents x > 7, which the unshaded circle starting from 7 and moving to the right.

Number line B represents x < 7 with the direction being to the left (opposite of A).

Number line C is synonymous with A, however the starting point is shaded which represents x ≥ 7

Number line D also follows up from B with D representing x ≤ 7

6 0

3 years ago

A bag contains 100 marbles. Some are blue, and the rest are white. There are 24 blue

Yanka [14]

Answer:

there would be 96 blue marbles and 4 white ones

Step-by-step explanation:

theres 100 marbles. every 24 marbles is 1 white marble. 24+1=25 25×4=100 24×4=96 1×4=4

7 0

3 years ago

Read 2 more answers

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

Lerok [7]

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

$IQR=Q_3-Q_1=16-6.5=9.5$

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

$IQR=Q_3-Q_1=15.5-8=7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

4 0

3 years ago