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serious [3.7K]
3 years ago
13

In how many ways can Anna arrange 2 math books, 3 physics books, and 5 chemistry books on her shelf if all books of the same sub

ject must be adjacent? (The books are distinguishable.)
​
Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

Answer:

  • 2 maths books can be arranged as (2!=2) ways
  • 3 physics books can be arranged as (3!=6) ways
  • 5 chemistry books can be arranged as (5!=120) ways
  • Books can be arranged in suject-wise in (3!=6) ways

Hence, total ways are (2×6×120×6) ways =8640 ways.

<h2><u>8640</u> is the right answer.</h2>
svetlana [45]3 years ago
7 0

Answer:

  • 8640 ways

Step-by-step explanation:

Arranging the books of each subject:

<u>Math</u>:

  • Combination of 2 books → 2! = 2

<u>Physics</u>:

  • Combination of 3 books → 3! = 6

<u>Chemistry</u>:

  • Combination of 5 books → 5! = 120

We also need to consider the subjects.

There are 3 subjects, kept separately, they will be arranged in 3! = 6 ways

<u>So the total number of combinations is:</u>

  • 2*6*120*6 = 8640
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3 years ago
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Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

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8 0
3 years ago
7,8,9,7,2,5,3,2, 2<br><br> Mean__<br> Median__<br> Mode__<br> Range__
serious [3.7K]

Answer:

Mean: 5

Median: 5

Mode: 2

Range: 7

Step-by-step explanation:

We find the mean by adding all the numbers together to get 45. Then we divide the 45 by the amount of numbers in the set, for this one it is 9. 45 divided by 9 equals 5.

To find the median we put the numbers in the set in order from least to greatest. Next, we find the middle number. median=5

To find the mode we find the number repeated the most. In this set the number that repeats the most is 2.

Range is found by subtracting the largest number and the smallest number. 9-2=7

4 0
3 years ago
Plss help it’s a test I’ll give 10 points
vodomira [7]

Answer:

Its the 3rd answer :)

<em>x = 26.94</em>

Step-by-step explanation:

<h2><em>This is because 25.5 + 1.44 = 26.94 :) (inverse operations ;))</em></h2>

<em />

4 0
3 years ago
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