Assigning "a" as cost of adult tickets and "c" the cost of children's tickets.
3a + 4c = 107
2a + 3c = 76
elimination method
2(3a + 4c = 107)
-3(2a + 3c = 76)
6a + 8c = 214
-6a - 9c = -228
----------------------
0 - c = - 14
c = 14
Then 2a + 3(14) = 76
2a = 76 - 42
2a = 34
a = 34/2
a = 17
Answer:
x=15
Step-by-step explanation:
subtract 1 from both sides so you are left with 2x=5x-45
then subtract 5x from both sides and you have -3x=-45
then finally divide -3 from -45 to get x=15
HAHA funny. The angle stays the same. 59 degrees.
Answer:
0.2
Step-by-step explanation:
Given the data :
Day : Mon Tue Wed Thu Fri Sat Sun
# of sick days 22 11 16 17 21 28 25
The expected count of sick days taken on Saturday is obtained thus :
Expected count = (row total * column total) / overall total
Here, the table is just one way :
Hence, we use :
Observed value / total days
Hence,
Expected count on Saturday = sick days on Saturday / total sick days
Expected count on Saturday = 28 / (22+11+16+17+21+28+25)
Expected count on Saturday = 28 / 140
= 0.2
Answer:
6 12 2
0 0 0
0 6 2
Step-by-step explanation:
multiply each single number in each row with the number in the same row but across the multiplication symbol.
3 x 2 = 6
6 x 2 = 12
etc
