Checking if the sequence is an arithmetic sequence
7 - 1 = 6
13 – 7 = 6
Therefore the sequence is arithmetic, with a_0 = 1 and d = 6
a_n = a_0 + (n-1)d
a_30 = 1 + (29)(6)
= 175
Therefore the 30th term is 175.
In this case, all letters are unique.
Start by holding the first letter:
E - XAM
E - XMA
E - MAX
E - MXA
E - AXM
E - AMX
So there are 6 combinations here.
Repeat for all 4 letters.
6 x 4 = 24
This is same as 4x3x2x1.
For 3 unique characters, it is 3x2x1.
For 5 unique characters, it is 5x4x3x2x1
And so on...
Answer:
9/8 I think I could be wrong tho
Answer:
Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.
Step-by-step explanation:
The equation f(x) given is:

For x = 0. the value of the expression is:

For x = 1, the value of the expression is:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.
In other words, there is at least one solution for the equation between x=0 and x=1.