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Lostsunrise [7]
3 years ago
15

{9-[8-(1/3+1/4)×6]}÷[8(1/3+1/2)×6]

Mathematics
1 answer:
enot [183]3 years ago
5 0

9 /80

or

= 0.1125

this should be the answer. Let me know if you need steps.

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Sort the following functions from asymptotically smallest to asymptotically largest, indicating ties if there are any. You do no
Serhud [2]

Answer:

b. n

d. 2^lgn

c. n^2.1

a. 4^2lgn

Step-by-step explanation:

Logarithm is a function of mathematics which is used to calculate inverse function of exponents. The asymptotically smallest function will be the one that has smallest or no exponents. The exponent function is calculated in reverse when log is applied. The function with highest exponents will be largest asymptotically.

3 0
3 years ago
Explain how to solve 3^x-4=6 using the change of base formula log base b of y equals log y over log b. include the solution for
Alexxandr [17]

Answer:

x = log 10/log 3

Step-by-step explanation:

3^x - 4 = 6

3^x = 10

We take log base 3 of both sides since log_3 3^x is simply x.

log_3 3^x = log_3 10

x = log_3 10

We have an answer for x, but it is a log base 3. We want log base 10.

Now we use the change of base formula.

log_b y = log y/log b

x = log 10/log 3

7 0
3 years ago
By talking to the sales clerk at the hardware store, you find out that the burglar has two hideouts — the lake house and the cab
DaniilM [7]
Cabin is your answer
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3 years ago
Trisha needs to make at least 50 gift bags for an event. Each gift bag will contain at least 1 thumb drive or 1 key chain. She w
DENIUS [597]
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5 0
3 years ago
Read 2 more answers
Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
3 years ago
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