[4 - (3c - 1)][6 - (3c - 1)]
[4 - 3c + 1][6 - 3c + 1]
[-3c + 4 + 1][-3c + 6 + 1]
[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
-3c[-3c] - 3c[7] + 5[-3c] + 5[7]
9c² - 21c - 15c + 35
9c² - 36c + 35
The constant variation for the relationship being shown is 4
Answer:
Domain : { -3, 0, 3}
Range : { 1 , 1 , 1 }
Function : These set of ordered pairs are functions as every x-value has only one y-value associated with it.
Answer:
8x +6y -28
Step-by-step explanation:
The outside factor applies to each inside term, so the equivalent expression is ...
-8(-x -3/4y +7/2) = 8x +6y -28
Applying the distributive property once again, we can also write the equivalent expression ...
= 2(4x +3y -14)
__
There are an infinite number of other equivalent expressions. The problem statement is non-specific as to the acceptable form.
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
