For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Add 72, 75, and 83, which equal 230. Then, since there are three values, you divide the total (230) by 3, which would equal 76.6 (cont), therefore meaning they can only raise their average (using the three tests, from a base grade of 0) to a 76.6 percent (or 77 if teacher rounds grade)
Answer:
I dont know yet give me a sec
Let's say you had the number 70.
70
/ \
10 7
/ \
5 2
Answer: 7,5,2 are your prime numbers
Answer: In what part do you need help with?
Step-by-step explanation:
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