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son4ous [18]
3 years ago
7

A swimming pool is 20 m long 15 m wide and 3 m deep. Find the cost of repairing the

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Cost of repairing the pool is

= Rs 12750

Correct me if i'm wrong

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42 degrees. Comment down if you need the explanation why
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A pen cost y dollars,how much will 25 such pens cost
kiruha [24]

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25y

Step-by-step explanation:

y×25=25y

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1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch
kykrilka [37]
Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle. 

Thus, half the angle formed by the chord at the centre of the circle is given by:

\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2}  \\  \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o

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\sin60^o= \frac{9}{r}  \\  \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392

Therefore, the radius of the circle is 10.4 cm to 1 d.p.


Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o

Now, 

\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm


Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

\sin40^o= \frac{y}{10}  \\  \\  \\ \Rightarrow y=10\sin40^o=6.428

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.
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3 years ago
Divide 7/9 by -11/7 then simplify
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Invert the divisor and then multiply 7/9 by your result:

 7      -7        -49
--- * ------ = ---------
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Find the GCF of 260,80,50
zaharov [31]

Answer:its 10

Step-by-step explanation:

6 0
2 years ago
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