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Lubov Fominskaja [6]
3 years ago
12

If f(x) = 7(x-1)+8, what is the value of f(1)

Mathematics
1 answer:
nevsk [136]3 years ago
8 0
F(1) = 8

Steps:
f(x) = 7(x-1) + 8
f(1) = 7(1-1) + 8
f(1) = 7(0) + 8
f(1) = 0 + 8
f(1) = 8
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LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

x^2 - x - 6

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

x^2 + 3x + 2x + 6

(x^2 + 3x) + (2x + 6)

x(x + 3) + 2(x + 3)

(x + 2)(x + 3)

x^2 - x - 6

x^2 - 3x +2x - 6

x(x - 3) + 2(x - 3)

(x + 2)(x - 3)

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

(x + 2) (this is common in both polynomials, so we would take just one of them as a factor.

(x + 3) and,

(x - 3)

Their product = (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)

4 0
3 years ago
(9x-9)(9×+9), your finding the difference between two squares. im have some trouble in how to solve it.​
sergejj [24]

Answer: Your answer is 0 (F.O.I.L) first. outer. inner. last. Or you could use what my teacher calls the magic box

Step-by-step explanation:

So for the boxes you multiply for example the top left box you multiply the 9 above it and the 9 to the left or like the top right box you multiply the -9 above it and the 9 on the outside of the box to the left

8 0
3 years ago
Make up two equations, one that is true and one that is false. do not state which equation is true and which is false.
Sophie [7]
3 + 6 = 9 - <span>1
4x3=36/3</span>
4 0
3 years ago
I need help..................
Viktor [21]

Answer:

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Step-by-step explanation:

7 0
3 years ago
A=(_3 2),b (4 _6),c=(5 _10)​
MAXImum [283]
First we find x of p:

x = 2 \times ( - 3) - \frac{1}{2} \times 4 + \frac{2}{5} \times 5 \\ = - 6 - 2 + 2 = - 6

then we find y of p:

y = 2 \times 2 - \frac{1}{2} \times ( - 6) - \frac{2}{5} \times ( - 10) \\ = 4 + 3 + 4 = 11

so

p = \binom{ - 6}{11}

and

|p| = \sqrt{ {( - 6)}^{2} + {11}^{2} } \\ = \sqrt{36 + 121} = \sqrt{157} = 12.53
6 0
2 years ago
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