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2 years ago

A cone with radius 4 ft and a height of 36 inches, use 3.14 as your value of pi, what is the volume?

1 answer:

4 0

Https://www.khanacademy.org/math/basic-geo/basic-geo-volume-surface-area/basic-geo-volumes/v/volume-....
use V=TT r2 h/3

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There are 45 animals at the pet store. 12% are dogs, 24% are cats, 36% are fish, and 28% are other animals. Find the number of a

vivado [14]

Step-by-step explanation:

Dogs: 12% of 45= 5.4

Cats: 24% of 45= 10.8

Fish: 36% of 45= 16.2

Other: 28% of 45= 12.6

8 0

2 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

What are the lengths of the other two sides of the triangle?

9966 [12]

To solve for area of a triangle u multiply base times height times 1/2

6 0

2 years ago

I would love if someone would help me

mart [117]

I’m hoping this helps (but hopefully now you can give the brainliest to the person above)
I’m not very familiar with the square roots method but I believe you try and isolate the term that is squared.

4 0

2 years ago

A square rug measures 8 feet by 8 feet. find the diagonal distance of the rug to the nearest whole number

Tanzania [10]

This is a right angle triangle and you use the Pythagorean theorem to solve for the hypotenuse (the diagonal)

A^2 + B^2 = C^2
8^2 + 8^2 = C^2
64 + 64 = C^2
128 = C^2
C = square_root (128)
C = 11 (to the nearest whole number)

The diagonal is 11 feet (to the nearest whole number)

7 0

2 years ago