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2 answers:
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Solution: We are given the population mean
Now, in order to find which shift's mean is closest to population mean, we will find the mean of each shift.
The mean of shift 1 is:
The mean of shift 2 is:
The mean of shift 3 is:
The mean of shift 4 is:
We clearly see the mean of shift 2 is close to the population mean. Hence the option B) Shift 2 is correct.
The complete question in the attached figure
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>