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alexandr402 [8]
3 years ago
6

Lee is making cookies and the recipe calls for 3/4 c. of chocolate chips. If she wants to make 2/3 of the recipe, what fraction

of a cup of chocolate chips will she need?
Mathematics
2 answers:
andreev551 [17]3 years ago
4 0
3/4×2/3=1/2 that is the answer

Andrej [43]3 years ago
3 0
2/3 of 3/4 C is .5, so 1/2 a cup? 
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bindus choir class is performing a concert. she wants to buy as many tickets as she can afford. if tickets cost $3.25 each and s
Galina-37 [17]

Answer:

4 tickets

Step-by-step explanation:

1 ticket is $3.25

2 ticket is $6.5

3 ticket is $9.75

4 ticket is $13

5 tickets is over and makes $16.25

5 0
3 years ago
An ornithologist has 4 bird feeders at separate locations. She wonders if birds are equally likely to visit each of the feeders.
Marianna [84]

Answer:

the x² test statistic 13.71

Option a) 13.71 is the correct answer.

Step-by-step explanation:

Given the data in the question;

Feeder                     1      2      3       4

Observed visits; o_i  60   90   92    58

data sample = 300

Expected e_i = 300 / 4 = 75

the x² test statistic = ?

X^2_{stat = ∑[ (o_i - e_i)²/e_i]

X^2_{stat = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]

X^2_{stat = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]

X^2_{stat = 13.7066 ≈ 13.71

Therefore, the x² test statistic 13.71

Option a) 13.71 is the correct answer.

7 0
3 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
the perimeter of equilateral triangular Garden is 18 ft. The side lengths are 3x feet. what is the value of x?
Yuliya22 [10]
X = 2

18 / 3 = 2

2 * 6 = 6

6 + 6 + 6 = 18

Hope this helps.
5 0
3 years ago
Read 2 more answers
Find BC<br> (triangle)<br> sides = 20mi, 22mi<br> inside = 95 degrees
Hunter-Best [27]
To solve this problem you need to know the law of cosines.

7 0
4 years ago
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