3 years ago

evaluate f(6) and f(6.1) and use the results to approximate f '(6). (round your answer to one decimal place.) f(x) = x(5 − x)

1 answer:

mote1985 [20]3 years ago

4 0

F(6) = 6(5 - 6) = 6(-1) = -6
f(6.1) = 6.1(5 - 6.1) = 6.1(-1.1) = -6.71

f'(6) ≈ (-6.71 - (-6))/(6.1 - 6) = -0.71/0.1 = -7.1

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?

azamat

Answer:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

${(x - a)}^{2} + {(y - b)}^{2} = {r}^{2}$

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Simplify to obtain:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

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Step-by-step explanation:

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