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Leokris [45]
3 years ago
12

evaluate f(6) and f(6.1) and use the results to approximate f '(6). (round your answer to one decimal place.) f(x) = x(5 − x)

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0
F(6) = 6(5 - 6) = 6(-1) = -6
f(6.1) = 6.1(5 - 6.1) = 6.1(-1.1) = -6.71

f'(6) ≈ (-6.71 - (-6))/(6.1 - 6) = -0.71/0.1 = -7.1
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faltersainse [42]

Answer:

a. 26.41

Step-by-step explanation:

25.75+.66=26.41

4 0
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How do u rewrite 0.72 repeating as a simplified fraction?
vampirchik [111]
8/11 is the answer

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When dividing by 11 the numerator will be one more than the first number in the decimal
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How does the shape of a cross-section of a 3D figure parallel to the base relate to the volume of the 3D figure?
Ket [755]

Answer:

The shape of each cross-section of a 3D figure,  relates to the volume because the area of the cross-section is determined by its shape and the area of this cross section is in the sum that calculates the volume of this 3D figure.

Step-by-step explanation:

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3 0
3 years ago
For funcitons f(x)=2x+3 and g(x)=-3x-2, please find (f∘g)(-1)
ratelena [41]

Answer:

\displaystyle (f\circ g)(-1) = 5

Step-by-step explanation:

We are given the two functions:
\displaystyle f(x) = 2x + 3\text{ and } g(x) = -3x - 2

And we want to find:
\displaystyle (f\circ g)(-1)

Recall that this is equivalent to:
\displaystyle (f\circ g)(-1) = f(g(-1))

Hence, find g(-1):
\displaystyle \begin{aligned} g(x) & = -3x - 2\\ \\ g(-1) & = -3(-1) - 2\\ \\ & = (3) - 2 \\ \\ & = 1 \end{aligned}

Substitute:
\displaystyle f(g(-1)) = f(1)

Find f(1):

\displaystyle \begin{aligned} f(x) & =  2x+ 3 \\ \\ f(1) & = 2(1) + 3 \\ \\ & = 5\end{aligned}

In conclusion:
\displaystyle (f\circ g)(-1) = 5

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3 years ago
Which of the following is a typical number of wildcards in one of the Sampson’s decks?
notsponge [240]

Answer:

2 wildcards

Step-by-step explanation:

Khan Academy

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