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V125BC [204]
3 years ago
13

Solve and recieve brain list ​

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

-x -7y=-15

y=3x-1

-x-7(3x-1)=-15

-x-21x+7=-15

-22x+7=-15

-22x=-15-7

-22x=-22

x=-22/-22

x=1

y=3x-1

y=3(1)-1

y=3-1

y=2

(1, 2)

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Find the upper 20%of the weight?
meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

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You spend $300 to start and costs $20 for each dog house
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Read 2 more answers
A test requires that you answer first Part A and then either Part B or Part C. Part A consists of 4 true false questions, Part B
erma4kov [3.2K]

Answer:  374416

Step-by-step explanation:

Given : A test requires that you answer first Part A and then either Part B or Part C.

Part A consists of 4 true false questions, Part B consists of 6 multiple-choice questions with one correct answer out of five, and Part C consists of 5 multiple-choice questions with one correct answer out of six.

i.e. 2 ways to answer each question in Part A.

For 4 questions, Number of ways to answer Part A = 2^4

5 ways to answer each question in Part B.

For 6 questions, Number of ways to answer Part B = 5^6

6 ways to answer each question in Part C.

For 5 questions, Number of ways to answer Part C = 6^5

Now, the number of ways to  completed answer sheets are possible :_

2^4\times5^6+2^4\times6^5\\\\=2^4(5^6+6^5)\\\\=16(15625+7776)\\\\=16(23401)=374416

Hence, the number of ways to  completed answer sheets are possible = 374416

8 0
3 years ago
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