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Vlad [161]
3 years ago
14

Consider the triangle A(4,0), B(-2,4), C(0,6) What will be the equation of the altitude BM?

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

BM: <u>y = (2/3) x + 16/3</u> with segment length of 2.77

Step-by-step explanation:

AC formula: m = (6-0)/(0-4) = -3/2

(y-0)/(x-4) = -3/2       y = (-3/2)x + 6   ... (1)

BM slope: BM⊥ AC   m = 2/3

BM formula: (y-4) / (x- -2) = (y-4) / (x+2) = 2/3

y-4 = 2/3 x + 4/3

<u>y = (2/3) x + 16/3</u>   ... (2)    -2≤x≤0.31

intercept of AC and BM (M) from (1) and (2): (-3/2)x + 6 = (2/3) x + 16/3

(13/6) x = 2/3      x = (2/3) / (13/6) = 4/13 ≈ 0.31

y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54

M (4/13 , 72/13) or (0.31 , 5.54)

segment BM = √(4/13 - -2)² + (72/13 - 4)² = √1300/169 = 2.77

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In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294
slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

a_4=54 and a_7=1458

To find a_{12}:

The given sequence is a geometric sequence.

The general term of the geometric sequence is a_n=a_1\ r^{n-1}.

If we have 2 terms of a geometric sequence a_n and a_k (n > K),

then we can write the general term as a_n=a_k\ r^{n-k}.

Here we have a_4=54 and a_7=1458.

So, n = 7 and k = 4 ( 7 > 4)

a_7=a_4\ .\ r^{7-4}

1458=54\ . \  r^3

This can be written as

$r^3=\frac{1458}{54}

$r^3=27

$r^3=3^3

Taking cube root on both sides of the equation, we get

r = 3

a_{12}=a_7\ .\ r^{12-7}

     =1458\ .\ r^5

     =1458\ .\ 3^5

a_{12}=354294

Hence the 12th term of the geometric sequence is 354294.

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What is the distance between the points (−7, 1) and (−7, −5) on the coordinate plane?
4vir4ik [10]

Answer:

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General Formulas and Concepts:
<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Step 2: Find distance </u><u><em>d</em></u>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

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