Step-by-step explanation:
First, note that a flexible statistical learning method refers to using models that take into account agree difference in the observed data set, and are thus adjustable. While the inflexible method usually involves a model that has no regard to the kind of data set.
a) The sample size n is extremely large, and the number of predictors p is small. (BETTER)
In this case since the sample size is extremely large a flexible model is a best fit.
b) The number of predictors p is extremely large, and the number of observations n is small. (WORSE)
In such case overfiting the data is more likely because of of the small observations.
c) The relationship between the predictors and response is highly non-linear. (BETTER)
The flexible method would be a better fit.
d) The variance of the error terms, i.e. σ2=Var(ϵ), is extremely high. (WORSE)
In such case, using a flexible model is a best fit for the error terms because it can be adjusted.
Answer:
area of pool = w(w+5) = w^2 + 5w square feet
Explanation:
The height of the pool is used as its width.
Assume that the width of the pool is w feet.
Now, we are given that the length of the pool is 5 feet longer than its width.
This means that:
length of the pool = w + 5 feet
The area of the rectangle is calculated as follows:
area = length * width
area = (w+5) * (w)
area = w^2 + 5w square feet
Hope this helps :)
12.9
Diameter is just the radius times 2
Answer:
1995, because you were paying $1.96 for 1 CPi, now you are paying around $1.16
Step-by-step explanation:
