Ask question

Ask question

All categories

mihalych1998 [28]

3 years ago

13

I don't know how to do this. I have the formula but I'm confused. Help?

1 answer:

Rom4ik [11]3 years ago

3 0

For the lateral area, don't include the base area. For the surface area, you should include it.

You might be interested in

Please help me with measurements

levacccp [35]

I dont know the answer but you may find this helpful:
-1 Quart = 1.13 British litres
-Fluid ounce = 0.028 Brtish litres
-1 gallon = 4.546 British litres
-1 Cup is 0.237 British litres

Now all the mesurments are the same i hope this helps a bit.

4 0

3 years ago

FIND THE MEASURE OF ANGLE 2 PLEASE HELP ASAP!

Bond [772]

Answer:

We know that the figure has a symmetry

angle 1 = angle 2

angle 1 =180°-(18°+90°) = 180° - 108°=72°

Therefore, <em><u>angle 2 =72°</u></em><em><u>.</u></em>

4 0

3 years ago

What is the equation of the line with a slope of 3/4 that goes through the point (4, 1) in slope-intercept form?

Svetach [21]

Answer:

$y=\frac{3}{4}x+-2$

Step-by-step explanation:

We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have m=3/4 and (4, 1). We input m and $x_{1} =4\\y_{1}=1$ .

$y-1=\frac{3}{4} (x-4)$

We now simplify the parenthesis and solve for y.

$y-1=\frac{3}{4} (x-4)\\y-1=\frac{3}{4}x+\frac{3}{4} (-4)$

We convert -4 into a fraction with 1 as the denominator.

$y-1=\frac{3}{4}x+\frac{3}{4} (\frac{-4}{1} )\\y-1=\frac{3}{4}x+\frac{-12}{4}\\y-1=\frac{3}{4}x+-3$

We add 1 to both sides to isolate y,

$y-1+1=\frac{3}{4}x+-3+1\\y=\frac{3}{4}x+-2$

This is slope intercept form. The line as slope 3/4 and y-intercept (0,2) or b=2.

4 0

3 years ago

WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!

Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: $a^2-b^2=(a+b)(a-b)$

Given $x^2-16=0$

Rewrite 16 as 4²

Therefore, $a^2=x^2$ and $b^2=4^2$

$\implies a = \sqrt{x^2}=x$

$\implies b=\sqrt{4^2} =4$

$\implies x^2-16^2=(x+4)(x-4)$

$\implies (x+4)(x-4)=0$

$\implies (x+4)=0 \implies x=-4$

$\implies (x-4)=0 \implies x=4$

<u>Method 2</u>

Given equation:

$x^2-16=0$

Add 16 to both sides:

$\implies x^2-16+16=0 + 16$

$\implies x^2=16$

Square root both sides:

$\implies \sqrt{x^2}=\sqrt{16}$

$\implies x=\pm4$

Therefore, x = -4, x = 4

6 0

2 years ago

ollegr [7]

784 divide by 7 is 112 so answer 112

7 0

3 years ago