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Nookie1986 [14]
3 years ago
8

A rectangular prism has a length of 112feet, a width of 212feet, and aheight of 8 inches. What is the volume of the prism in cub

ic inches?
pls hurry :)
Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

27,353,088 cubic inches

Step-by-step explanation:

<u>How to find the volume of a rectangular prism</u>

To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units.

<u>Solve</u>

In this case, The volume of a rectangular prism with a length of 112feet,

width of 212 feet, and height of 8 inches:

But in this case, we need to convert both the length and width to inches.

If 1ft = 12in

Then, 112ft = 1344in  (Multiply 112 by 12)

Also, 212ft = 2544 (Multiply 212 by 12)

So, the volume = 1344 x 2544 x 8

Calculated out this gives a volume of 27,353,088 cubic inches.

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Answer:

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Step-by-step explanation:

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3 years ago
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ExtremeBDS [4]

Answer:

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Step-by-step explanation:

(40/5)-7+2

PEMDAS says parentheses first, so divide inside the parentheses

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Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

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(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

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Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

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Z = -1 has a pvalue of 0.1587

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This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

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