Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)
30°
A strait line is 180°
75°+75°=150°
180°-150°=30°
Answer:advadfvzcs
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Step-by-step explanccccdcsdadrfaration:
X12
Answer:
![y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
Step-by-step explanation:
(1 + x²)dy +xydx= 0

Integrate both side
![lny=-\frac{1}{2} ln(x^2+1)+c\\y=\frac{c}{\sqrt[]{x^2+1} }](https://tex.z-dn.net/?f=lny%3D-%5Cfrac%7B1%7D%7B2%7D%20ln%28x%5E2%2B1%29%2Bc%5C%5Cy%3D%5Cfrac%7Bc%7D%7B%5Csqrt%5B%5D%7Bx%5E2%2B1%7D%20%7D)
Answer:
1122
Step-by-step explanation: