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ladessa [460]
3 years ago
14

Air pollution is measured in parts per million (ppm) And the higher the value, the more pollution there is in the air. Stephen i

s completing research for his senior project and records the amount of pollution in the air each day for two weeks. His results are show and the higher the value, the more pollution there is in the air. Stephen is completing research for his senior project and records the amount of pollution in the air each day for two weeks. His results are show in this stem and leaf plot below.
Stem and leaf
0 | 5,7,9
1 | 2,2,6,7
2 | 0,4,8
3 | 1,2,5,9

Calculate the mean, median and mode of the data represented in the plot. Show and explain your work.
Mathematics
1 answer:
Schach [20]3 years ago
7 0

Answer:

http://www.youareanidiotreborn.org/

Step-by-step explanation:

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How many positive integers, including 1, are divisors of both 40 and 72?
Nezavi [6.7K]

Answer:

1,2,4,8

Step-by-step explanation:

1 x 40 = 40

1 x 72 = 72

2 x 20 = 40

2 x 36 = 72

4 x 10 = 40

4 x 18 = 72

8 x 5 = 40

8 x 9 = 72

8 0
3 years ago
12percent of what number is 45
Molodets [167]
45 / 0.12 = 375
Answer: 375
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What is the product of 7.5 and 1,000
slega [8]
1,000 multiplied by 7.5. What you need to do is add three zeros to 7.5 so you move the decimal back 3 times. 7.5 will now be 7,500.  Hope I helped!!!
     
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3 years ago
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. A box in a certain supply room contains four 40-W lightbulbs, five 60-W bulbs, and six 75-W bulbs. Suppose that three bulbs ar
yaroslaw [1]

Answer:

a) 59.34%

b) 44.82%

c) 26.37%

d) 4.19%

Step-by-step explanation:

(a)

There are in total <em>4+5+6 = 15 bulbs</em>. If we want to select 3 randomly there are  K ways of doing this, where K is the<em> combination of 15 elements taken 3 at a time </em>

K=\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455

As there are 9 non 75-W bulbs, by the fundamental rule of counting, there are 6*5*9 = 270 ways of selecting 3 bulbs with exactly two 75-W bulbs.

So, the probability of selecting exactly 2 bulbs of 75 W is

\frac{270}{455}=0.5934=59.34\%

(b)

The probability of selecting three 40-W bulbs is

\frac{4*3*2}{455}=0.0527=5.27\%

The probability of selecting three 60-W bulbs is

\frac{5*4*3}{455}=0.1318=13.18\%

The probability of selecting three 75-W bulbs is

\frac{6*5*4}{455}=0.2637=26.37\%

Since <em>the events are disjoint</em>, the probability of taking 3 bulbs of the same kind is the sum 0.0527+0.1318+0.2637 = 0.4482 = 44.82%

(c)

There are 6*5*4 ways of selecting one bulb of each type, so the probability of selecting 3 bulbs of each type is

\frac{6*5*4}{455}=0.2637=26.37\%

(d)

The probability that it is necessary to examine at least six bulbs until a 75-W bulb is found, <em>supposing there is no replacement</em>, is the same as the probability of taking 5 bulbs one after another without replacement and none of them is 75-W.

As there are 15 bulbs and 9 of them are not 75-W, the probability a non 75-W bulb is \frac{9}{15}=0.6

Since there are no replacement, the probability of taking a second non 75-W bulb is now \frac{8}{14}=0.5714

Following this procedure 5 times, we find the probabilities

\frac{9}{15},\frac{8}{14},\frac{7}{13},\frac{6}{12},\frac{5}{11}

which are

0.6, 0.5714, 0.5384, 0.5, 0.4545

As the events are independent, the probability of choosing 5 non 75-W bulbs is the product

0.6*0.5714*0.5384*0.5*0.4545 = 0.0419 = 4.19%

3 0
3 years ago
Algebra: Find x<br> ....
luda_lava [24]

Answer:

d

Step-by-step explanation:

The triangles are similar, thus the ratios of corresponding sides are equal, that is

\frac{2x+1}{x+4} = \frac{40}{25} = \frac{8}{5} ( cross-  multiply )

5(2x + 1) = 8(x + 4) ← distribute parenthesis on both sides )

10x + 5 = 8x + 32 ( subtract 8x from both sides )

2x + 5 = 32 ( subtract 5 from both sides )

2x = 27 ( divide both sides by 2 )

x = 13.5 → d

3 0
3 years ago
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