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natali 33 [55]
3 years ago
6

Keira , larry and gita picked apples at an orchard. keira picked twice as many pounds as larry and 3 times as many as gita. the

total weight of the apples
they picked was 8,360 pounds. how many pounds of apples did each person pick. please explain how you solved it
Mathematics
1 answer:
Natalija [7]3 years ago
7 0
Number of apples in pounds picked up by Keira = K
Number of apples in pounds picked up by Larry = L
Number of apples in pounds picked up by Gita = G
Total number of apples they picked all together in pounds = 8360
Now from the given question, we know
Number of apples picked up by Kiera = 2L
So
K = 2L
L = K/2
Again Kiera picked up 3 times as many apples as Gita picked.
So,
K = 3G
G = K/3
Now if we add all the apples in pounds picked up by the three of them.
Then
K + L + G = 8360
K + (K/2) + K/3) = 8360
(6K + 3K + 2K)/6 = 8360
11K/6 = 8360
11K = 8360 * 6
11K = 50160
K = 4560
Then
L = K/2
   = 4560/2
   = 2280
G = K/3
   = 4560/3
   = 1520
Now we can say that
Kiera picked 4560 pounds of apple
Larry picked 2280 pounds of apple
Gita picked 1520 pounds of apple
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From the question, we identify the probabilities as follows;

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Now, plugging these values, we have

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Answer:

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A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

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A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

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∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

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Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

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