Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The capacity of an Airliner is k = 300 passengers
The sample size n = 320 passengers
The probability the a randomly selected passenger shows up on to the airport

Generally the mean is mathematically represented as
=>
=>
Generally the standard deviation is

=> 
=> 
Applying Normal approximation of binomial distribution
Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

Here 
=>
Now applying continuity correction we have
=> ![P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B%5B300.5%5D%20-%20307.2%7D%7B3.50%7D%20%29)
=> 
From the z-table

So

He'll get $14.03 because 20.25 is what he gave but it only came up to 6.22 so 20.25-6.22=14.03
A think it is all of the above because each rope is the same amount
(12,200 + 16,211 + 12,050 + 11,350 + 13,325) / 5 = 65136/5 =
13027.2 <== this is the mean (average)
11,350 , 12,050 , 12,200 , 13,325, 16,211
median (middle number) = 12,200
there is no mode...a mode is a number that appears most often...all the numbers appear once in this data.