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photoshop1234 [79]

3 years ago

12

Use the models above to explain why a 5×2/3 equals 10×1/3

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

I kind of need the models to help with this one

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What is the slope? <br> please hurry!<br> y=-x - 3

artcher [175]

Answer:

Step-by-step explanation:

slope =

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y + 3 = (x - 2) is in this form

with slope m =

4 0

3 years ago

Read 2 more answers

HELP PLEASE <br><br><br> Simplify.

maksim [4K]

Simplifying
2x + -3(3 * 0.6x + 2.7)

Multiply 3 * 0.6
2x + -3(1.8x + 2.7)

Reorder the terms:
2x + -3(2.7 + 1.8x)
2x + (2.7 * -3 + 1.8x * -3)
2x + (-8.1 + -5.4x)

Reorder the terms:
-8.1 + 2x + -5.4x

Combine like terms: 2x + -5.4x = -3.4x
-8.1 + -3.4x

7 0

3 years ago

Can someone help me solve this step by step? tyyyy

vlabodo [156]

Answer:

x=4/7

Step-by-step explanation:

6 - 2/3(x+5) = 4x

First I want to clear the fraction so I will multiply everything by 3

3*6 -3* 2/3(x+5) = 3*4x

18 - 2(x+5) =12x

Distribute

18 - 2x-10 =12x

Combine like terms

8 -2x = 12x

Add 2x to each side

8 -2x+2x =12x+2x

8 = 14x

Divide each side by 14

8/14 =14x/14

8/14=x

Divide top and bottom by 2

4/7=x

8 0

4 years ago

What is the distance between (2.6) and (7,6)?

scZoUnD [109]

Answer:

5 units

Step-by-step explanation:

(2,6) and (7,6)

Since the y coordinates are the same, we only need to look at the x coordinates

The distance between 2 and 7 is

7-2 =5

5 units

6 0

3 years ago

Read 2 more answers

Mariulka [41]

Answer:

$A = 74.7^\circ$

$B = 42.5^\circ$

$C = 62.8^\circ$

Step-by-step explanation:

Given

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

For AB

$A = (-1,2) \to (x_1,y_1)$

$B = (2,8) \to (x_2,y_2)$

$d = \sqrt{(-1 - 2)^2 + (2 - 8)^2$

$d = \sqrt{(-3)^2 + (-6)^2$

$d = \sqrt{45$

So:

$AB = \sqrt{45$

For BC

$B = (2,8) \to (x_2,y_2)$

$C = (4,1) \to (x_3,y_3)$

$BC = \sqrt{(2 - 4)^2 + (8 - 1)^2$

$BC = \sqrt{(-2)^2 + (7)^2$

$BC = \sqrt{53$

For AC

$A = (-1,2) \to (x_1,y_1)$

$C = (4,1) \to (x_3,y_3)$

$AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2$

$AC = \sqrt{(-5)^2 + (1)^2$

$AC = \sqrt{26$

So, we have:

$AB = \sqrt{45$

$BC = \sqrt{53$

$AC = \sqrt{26$

By representation

$AB \to c$

$BC \to a$

$AC \to b$

So, we have:

$a = \sqrt{53$

$b = \sqrt{26$

$c = \sqrt{45$

By cosine laws, the angles are calculated using:

$a^2 = b^2 + c^2 -2bc \cos A$

$b^2 = a^2 + c^2 -2ac \cos B$

$c^2 = a^2 + b^2 -2ab\ cos C$

$a^2 = b^2 + c^2 -2bc \cos A$

$(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A$

$53 = 26 +45 - 2 * 34.21 * \cos A$

$53 = 26 +45 - 68.42 * \cos A$

Collect like terms

$53 - 26 -45 = - 68.42 * \cos A$

$-18 = - 68.42 * \cos A$

Solve for $\cos A$

$\cos A =\frac{-18}{-68.42}$

$\cos A =0.2631$

Take arc cos of both sides

$A =\cos^{-1}(0.2631)$

$A = 74.7^\circ$

$b^2 = a^2 + c^2 -2ac \cos B$

$(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B$

$26 = 53 +45 -97.67 * \cos B$

Collect like terms

$26 - 53 -45= -97.67 * \cos B$

$-72= -97.67 * \cos B$

Solve for $\cos B$

$\cos B = \frac{-72}{-97.67}$

$\cos B = 0.7372$

Take arc cos of both sides

$B = \cos^{-1}(0.7372)$

$B = 42.5^\circ$

For the third angle, we use:

$A + B + C = 180$ --- angles in a triangle

Make C the subject

$C = 180 - A -B$

$C = 180 - 74.7 -42.5$

$C = 62.8^\circ$

8 0

3 years ago