Width = x
Length = x+18
Assuming the table is rectangular:
Area = x(x + 18)
Therefore:
x(x + 18) <span>≤ 175
x^2 + 18x </span><span>≤ 175
Using completing the square method:
x^2 + 18x + 81 </span><span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
</span><span>
But x > 0 (there are no negative measurements):
</span><span>
Therefore, the interval 0 < x </span><span>≤ 7 represents the possible widths.</span><span>
</span>
I can't answer that because there is no other part to the question
32 29/30 its 32 and 5/30+24/30
M<APB + m<BPC = 90 complementary angles
m<FPB + m<BPC = 180 linear pair
m<APB = m<EPD vertical angles
m<FPD = m<APC right angles are congruent
m<EPC + m<EPF = 180 linear pair
m<BPC = m<EPD vertical angles
Answer:
F^-1(x)=0.125x-0.125
Step-by-step explanation:
Y=8x+1
X=8y+1
8y=x-1
Y=0.125x-0.125
