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AnnZ [28]
3 years ago
7

Please help, math isn’t my strong suit.

Mathematics
1 answer:
ikadub [295]3 years ago
8 0
This is what I got:
sin 54 ° = 0.80901699

I’m not sure what the [?] is cause I see no number beneath it either but I hope this somehow helps

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For a circle of raduis 6feet, find the arc length of a central angle of 6
murzikaleks [220]
Length of a circumference=2πr
r=radius=6 feet.
lengt of this circumference=2π6 feet=12π feet.

1 circumference=360º; then:

360º-------------------12π feet
6º----------------------    x

360º * x=6º * 12π feet
x=(6º * 12π feet) / 360º=π/30  feet (≈0,105 feet).

Solution: π/30 feet
4 0
3 years ago
How to solve this trigonometric equation cos3x + sin5x = 0
mrs_skeptik [129]

Answer:

  x = {nπ -π/4, (4nπ -π)/16}

Step-by-step explanation:

It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:

  cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)

  = cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)

  = sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))

  = (sin(x) +cos(x))·(sin(4x) +cos(4x))

Each of the sums in this product is of the same form, so each can be simplified using the identity ...

  sin(x) +cos(x) = √2·sin(x +π/4)

Then the given equation can be rewritten as ...

  cos(3x) +sin(5x) = 0

  2·sin(x +π/4)·sin(4x +π/4) = 0

Of course sin(x) = 0 for x = n·π, so these factors are zero when ...

  sin(x +π/4) = 0   ⇒   x = nπ -π/4

  sin(4x +π/4) = 0   ⇒   x = (nπ -π/4)/4 = (4nπ -π)/16

The solutions are ...

  x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n

5 0
2 years ago
ANSWER ASAP PLSSS
Andrei [34K]

vbbbbbbbbbbbbbbbbbdnnnnnAnswer:

Step-by-step explanation:

8 0
3 years ago
Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si
Inessa [10]

Using relations in a right triangle, it is found that:

  • \sin{x} = \frac{6}{10} = 0.6
  • \cos{y} = \frac{6}{10} = 0.6
  • Since x and y are complementary angles, we have that sin(xº) = cos(yº).

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

  • The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.
  • The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.
  • The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The hypotenuse in this problem is given as follows:

h^2 = 6^2 + 8^2

h = \sqrt{100}

h = 10.

The sine of x is:

\sin{x} = \frac{6}{10} = 0.6

The cosine of y is:

\cos{y} = \frac{6}{10} = 0.6

Since x and y are complementary angles, we have that sin(xº) = cos(yº).

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

8 0
2 years ago
18x-16=-12x-4<br> what is the value of x?<br>need help asap
amm1812
18x - 16 = -12x - 4 ---> Add 12x to both sides
30x - 16 = -4 ---> Add 16 to both sides
30x = 12 ---> Divide both sides by 30

x = 0.4
3 0
3 years ago
Read 2 more answers
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