Answer:
L = 15
Step-by-step explanation:
P = 2L + 2W
you know that P = 50, W=10
So you have to replace those values on the equation
50 = 2L + 2*(10) --> Replace P and W
50 = 2L + 20 --> Multiply and now you are going to separate the unknown and the constants.
Remember that if you send a constant to the other side of the equal the sign will change to its opposite
50 - 20 = 2L --> Solve the constants
30 = 2L --> Now for the L, you have to leave it alone, so the 2 that is multiplying you have to send it to the other side of the equal but with the opposite operation, the opposite operation of multiplying is dividing, so you have:
30/2 = L
L= 15
20% of 32= 6.4
20% x 32
20 /100 x 32
Reduce the fraction
1 /5× 32
=32/5
=6.4
Answer:
Neither
Step-by-step explanation:
To tell if lines are perpendicular or parallel just from the equations, you need to look at the slopes. So get the equations into slop-intercept form
(y = slope * x + y-intercept)
2x = 14 + y
-14 -14
2x - 14 = y OR y = 2x - 14
*So the slope of the first equation is 2*
4x + 2y = 10
-4x -4x
2y = -4x + 10
/2 /2
y = -4/2 + 10
*So the slope is -2*
For the lines to be parallel, the slopes have to be the same. For them to be perpendicular, the slopes have to be opposite (negative is the opposite of positive and vice versa) and reciprocal (A flipped fraction, so the reciprocal of 2 would be 1/2)
Look at all the choices
we know that at t = 0, the height of the rock is 16
choices H and I do not have a value of 16 at t = 0.
H: h(0) = -5.2(0)² + 24(0) - 12 = -12
I: h(0) = -4.2(0)² + 26(0) - 20 = -20
so we are left with F and G
if we take choice F and plug in t = 1
h(1) = -4.7(1)² - 25(1) + 16 = -13.7
if we take choice G and plug in t = 1
h(1) = -4.7(1)² + 25(1) + 16 = 36.3
only choice G works for us since it has 36.3 at t = 1
you could have also put these points in a graphing calculator and then use the quadratic regression feature to get an equation that will model this data
We have the expressions:
Now, with this we operate as follows:
a)
Then, the axis is x = -3 and the vertex (-3, 6)
b)
Then, the vertex is (2, 5) and the axis is x = 2.
c)
Then, the vertex is (2, -4) andd the axis is x = 2.
d)
Then, the vertex is (-7/2, -57/4) and the axis is -7/2.
