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2 years ago

Please help due in a few minutes!!

Mathematics

1 answer:

marusya05 [52]2 years ago

7 0

41/50 is the answer

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Sketch the curve with the given vector equation. Indicate with an arrow the direction in which t increases. r(t) = 4 cos(t)i + 4

slega [8]

Answer:

The equation to this question is " $x^2+y^2=16$ "

Step-by-step explanation:

Given value:

$\to r(t) = 4 \cos (t)i + 4 sin(t)j + k\\where \\\\\to x(t)= 4 \cos t\\\to y(t) = 4 \sin t\\\to z(t)=1\\$

$\to x^2+y^2= 16 \cos^2 t +16 \sin^2 t\\\\\to x^2+y^2= 16 (\cos^2 t +\sin^2 t)\\\\\therefore (\cos^2 t +\sin^2 t =1)\\\\\to x^2+y^2= 16 (1)\\\\\to x^2+y^2= 16\\\\\to z=1$

So, the curve $r(t) = 4 \cos (t)i + 4 sin(t)j + k$ is basically a circle, which is defined in the attachment file.

7 0

3 years ago

What is the length of the diagonal, d, of the rectangular prism shown below?

Svetlanka [38]

Answer: I think it’s 5 I’m not sure

Step-by-step explanation:

6 0

3 years ago

What is the answer of my question

Ipatiy [6.2K]

Answer:

1000

Step-by-step explanation:

see how to solve in pic

4 0

3 years ago

A tower stand on a horizontal plane. P is the top and Q is the bottom of the tower. A and B are two points on this plane such th

pochemuha

Answer:

32√5

Step-by-step explanation:

We have the right triangles PQA and PQB as well as the given right triangle QAB.

cot(PAQ) = 2/5 = QA/PQ

cot(PBQ) = 3/5 = QB/PQ

cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3

cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB

QA / QB = 2/3

QA = (2/3) QB

QB = (3/2) QA

By the Pythagorean Theorem we have:

(QA)² + 32² = (QB)²

(QA)² + 32² = (3/2 QA)²

(QA)² + 1024 = (9/4) (QA)²

(5/4) (QA)² = 1024

(QA)² = (4/5)1024 = 4096/5

QA = 64/√5

Solve for PQ.

cot(PAQ) = QA/PQ

PQ = QA / cot(PAQ)

PQ = (64/√5) / (2/5) = 32√5

The height of the tower is 32√5.

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4 years ago

Order the values least to greatest

Paul [167]

Answer:

9.013, 9.13, 9.1342, 9.2

8 0

3 years ago