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3 years ago

Please help me......

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

7 0

Answer:

<BAC=1/2 <BOC=1/2 X=X/2(INSCRIBED ANGLE IS HALF OF CENTRAL ANGLE)

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Alan drew a scale drawing of a house and its lot. The scale he used was 1 millimeter: 5 meters. In the drawing, the lawn in the

Marat540 [252]

50 meters

Explanation

you can easily solve this by using a rule of three.

Step 1

Let

$\begin{gathered} 1\text{ milemeter}\rightarrow5\text{ meters} \\ \text{the proportion is} \\ \frac{1\text{ mm}}{5\text{ mt}} \end{gathered}$

x represents the length of the actual lawn

then

$\begin{gathered} 10\text{ mm}\rightarrow x\text{ mt} \\ \text{the proportion is} \\ \frac{10\text{ mm}}{\text{xmt}} \end{gathered}$

the proportion is the same, so

Step 2

$\begin{gathered} \frac{1}{5}=\frac{10}{x} \\ \text{solve for x} \\ 1\cdot x=5\cdot10 \\ x=50 \end{gathered}$

so, the length is 50 meters

6 0

2 years ago

A table is on sale for $179.20, which is 72% less than the regular price. What is the regular price?

Marianna [84]

Answer:

640

Step-by-step explanation:

price ÷ 1 - percent (as decimal)

179.20÷(1-0.72) = 640

8 0

3 years ago

Read 2 more answers

Pls help me

deff fn [24]

Answer:

Angle 1: Can be measures of triangle: 84

Cannot be angle measures of triangle: 49, 47

Angle 2: Can be measures of triangle: none

Cannot be angle measures of triangle: 50,89,50

Angle 3: Can be angle measures of triangle: 75, 15, 45

Cannot be angle measures of triangle: none

Angle 4: Can be angle measures of triangle: none

Cannot be angle measures of triangle: 25, 22, 133

5 0

2 years ago

A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea

marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that $n = 11$

Each question has five choices.

This means that $p = \frac{1}{5} = 0.2$

(a) Find P (6)

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097$

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

$P(X \leq 3) + P(X > 3) = 1$

We want P(X > 3). So

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859$

$P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362$

$P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953$

$P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389$

Then

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611$

P(More than 3) = 0.1611

8 0

4 years ago

13/8+(3/2+7/4)<br> Answer

nasty-shy [4]

Answer:

29/8

Step-by-step explanation:

13/8+(3/2+7/4)

13/8+(6/4+7/4) (convert common denominators)

13/8+13/4 (add parentheses)

13/8+26/8 (convert common denominators)

29/8 (add)

3 0

3 years ago