Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
<h2><em>4^-8 = 1/(4^8)</em></h2><h2><em></em></h2><h2><em>(4^6) x (1/4^8) = (4^6)/(4^8)</em></h2><h2><em></em></h2><h2><em>Simplify. Note that when dividing with powers, subtract the powers (if the base is the same number)</em></h2><h2><em></em></h2><h2><em>(4^6)/(4^8) = 4^(6 - 8)</em></h2><h2><em></em></h2><h2><em>4^(6 - 8) = 4^(-2)</em></h2><h2><em></em></h2><h2><em>4^(-2) = 1/(4^2)</em></h2><h2><em></em></h2><h2><em>1/(4²) = 1/16</em></h2><h2><em></em></h2><h2><em>1/16 is your answer</em></h2><h2><em> HOPE IT HELPS (◕‿◕✿) </em></h2><h2><em> SMILE!!</em></h2>
