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maksim [4K]
3 years ago
10

The volume of this rectangular prism is 36 cm^2. How many ½ cm cubes will fit in this rectangular prism? Show your reasoning.

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.

Step-by-step explanation:

Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.

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Kisachek [45]

Answer:

A

Step-by-step explanation:

Use the range

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3 years ago
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If B is the midpoint of AC, AC= CD, AB=3x+4, AC= 11x-17, and CE= 49 , find DE
melisa1 [442]

Answer:

Ehhh

Step-by-step explanation:

4 0
3 years ago
henry can write 5 pages of his novel in 3 hours at this rate how many pages can henry write in 8 hours​
My name is Ann [436]

Answer:

Henry can write 13 pages in 8 hours.

it can also be written as 13.3

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3 years ago
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Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
How do you solve this?
Law Incorporation [45]
Find the soluiton

2x+2y=16
3x-y=4

x+y=8
<u>3x-y=4+</u>
4x=12
x=3
3(3)-y=4
9-y=4
y=5
(3,5)
test them to see if get true statment
obviously the first equatons of 1,2,4 work
1 doesn't work
2, works
4. doesn't work

2 is the same as the first except both euations are just doubled

answer is 2
6 0
3 years ago
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