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liq [111]
3 years ago
8

A rectangular frame that is 2/3 feet Long has an area of 1/2 square feet.What is the width​

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

1.3333 Repeated

Step-by-step explanation:

To find area you just do A= L*W so you just do the revirse W= \frac{a}{l}

You might be interested in
Find the exponential function that satisfies the given conditions: Initial value = 37, increasing at a rate of 5% per year
beks73 [17]

The required function is:

Option 3: f(t) = 37. (1.05)^t

Step-by-step explanation:

The initial value and rate is used to write exponential function

Here

Given

Initial value = 37

Rate = r = 5%

When the rate is 5%, the next year the quantity will be 1+0.05 = 1.05 time of the current quantity.

So,

The function can be written as:

f(t) = 37. (1.05)^t

For initial value, put t=0

f(t) = 37. (1.05)^0\\f(t) = 37 * 1\\f(t) = 37

Hence,

The required function is:

Option 3: f(t) = 37. (1.05)^t

Keywords: Functions, exponential functions

Learn more about functions at:

  • brainly.com/question/11280112
  • brainly.com/question/11286417

#LearnwithBrainly

4 0
3 years ago
24x3 + 18x2 - 6x <br>Factor Polynomials Completely​
andreev551 [17]
You answer for 24x3+18x2-6x would be 102x
8 0
3 years ago
The area of a rectangular painting is 5,766 cm2. If the length of the painting is 93 cm, what is its width?
Neko [114]

Answer:

62 cm

Step-by-step explanation:

62 x 93 = 5,766

8 0
4 years ago
Can someone please answer this question please answer it correctly and please show work please help me I need it
love history [14]

Answer:

The answer would be -10.

Step-by-step explanation:

It's -10 because -8-(-10) = 2

That is equal to -8 + 10 = 2 because two negative together make a positive number.

7 0
3 years ago
Read 2 more answers
Aria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there wer
denpristay [2]

Answer:

8,800,000cars

Step-by-step explanation:

Given the initial amount of cars = 80,000,000

If there is 10 % increase in the first year;

Increment = 10% of 80,000,000

Increment = 0.1 * 80,000,000

Increment = 8,000,000

Amount of car in year 2 = 80million + 8million = 88million

Year3;

Amount of car in year 3 = 88,000,000+(10%of88million)

Amount of car in year 3 = 88,000,000+8,800,000

Amount of car in year 3 =96,800,000

Differences in the number of cars = 96,800,000 - 88,000,000

Differences in the number of cars = 8,800,000cars

<em>Hence there are 8,800,000cars in years 3 than year 2</em>

7 0
3 years ago
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