Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!
Answer:
I think the answer is 0.00000824
Step-by-step explanation:
Answer: 5y= -40
Step-by-step explanation: When you add the -3 and + 3 they equal zero and that single y has an imaginary 1 in front of it so 1y+4y=5y. And -2 +-38 is -40. :)
I honestly forgot about this but I can try and help you or just use an app
Answer:
63/2
Step-by-step explanation:
