Which what is the algebraic expression for nine less dense some number

Xavier wants to buy a pair of jeans. The original price of the jeans is

pav-90 [236]

Answer:17$

Step-by-step explanation:

17 is one fourth if 68

6 0

3 years ago

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What is the solution for -3x ≥ 36? x ≤ -12 x ≥ -12 x ≤ -108 x ≥ -108

konstantin123 [22]

Answer:

Step-by-step explanation:

Let

V

be the number of vertices of a polyhedron,

F

the number of faces of that polyhedron, and

E

be the number of edges. The quantity

χ

=

V

−

E

+

F

is called the Euler characteristic (of a polyhedron). In the case of convex polyhedra,

χ

=

2

.

Consider, for example, a tetrahedron (which is the simplest solid). It has 4 faces,

1

2

(

4

)

(

3

)

=

6

edges, and

1

3

(

4

)

(

3

)

=

4

vertices. Thus we have

V

−

E

+

F

=

4

−

6

+

4

=

2

.

Euler's formula holds for all Platonic solids (tetrahedron, cube, octahedron, dodecahedron, and icosahedron). Since a cube and an octahedron are dual polyhedra (each is formed by connecting the centers of the faces of the other), their

V

and

F

values are equal to the

F

an

V

values of the other. (The same is true for the dodecahedron and icosahedron).

3 0

3 years ago

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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

7 0

3 years ago

Please help ! 100 points

Leokris [45]

Answer:

x = 109 degrees

Step-by-step explanation:

180-48-23

5 0

4 years ago

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The sum of five times a number and ten is twenty-five. Find the number.

kotegsom [21]

Answer:

Question: The sum of 10 and 5 times a number is 25. Find the number.

Answer: x = 3

Step-by-step explanation:

10 + 5x = 25

5x = 25 - 10

5x = 15

x = 3

5 0

3 years ago