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2 years ago

Please Help! Question In Picture!

Mathematics

1 answer:

Svet_ta [14]2 years ago

5 0

Answer:

After 12years sam pitches house in rs882000

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4:5 12:? 32:40 ?:55 ?:95<br> The answer in blanks

posledela

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2 years ago

Read 2 more answers

When pouring water from one five gallon bucket to another, a person tends to pour at a faster rate at first and then slow down i

Nitella [24]

I will assume that 0.62 is an exponent then

amount left after t seconds = f(6) = 5 - 0.82(6)^0.62

= 2.51 gallons to nearest hundredth.

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3 years ago

Cam has 32 dollars. How many roses can he afford to buy?

Vlad [161]

Answer:

8 roses

Step-by-step explanation:

roses cost about 4 dollars, and 8 times 4=32

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2 years ago

The pizza parlor is running a special on 3-toppings pizzas. The topping choices include pepperoni, sausage, bacon mushrooms, oni

choli [55]

Answer:

Well there are 6 toppings. For one person to select sausage, it is \frac{1}{6} . For two people, multiply them together and the probability is \frac{1}{36}

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3 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago