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3 years ago

HELP ME, seriously no one has helped me yet

Mathematics

2 answers:

SOVA2 [1]3 years ago

6 0

Answer:

1. Lunch ($16)

2. Coffee ($4)

3. how much money did she have left?

she had ($12) left

Step-by-step explanation:

1. To get the amount of money she used on lunch you have to look at the word problem it says "she spent 1/2 of her money on lunch" her total is $32 dollars and 1/2 is .5 as a decimal and 50% as a percentage so 50% of 32 is (16) so she spent $16 dollars on lunch alone.

2. To find how much money she used on Coffee you need to read the context of the problem its asking for "how much did she use of the money that is left from her lunch" so she has $16 dollars she used from lunch so now it wants you to find 1/4 of $16 dollars or 25% of 16 and 25% of 16 is (4)

so she spent 4 dollars of what was left so the answer is 4.

3. To find how much is left add up 16 and 4 and you get 20 then subtract it by the original number which is 32 so it should look like this 32 - 20 = 12

so the money she has left is $12 dollars.

larisa [96]3 years ago

3 0

Answer: Lunch:$16 Coffee: $4 Julie had $12 left.

Step-by-step explanation:

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Read 2 more answers

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

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Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$