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Klio2033 [76]
3 years ago
13

Find any values of x that must be excluded from the domain. This part really confuses me.

Mathematics
2 answers:
aliina [53]3 years ago
5 0
That means the ones that you can't use
like the ones that cause sqare rot of negative or divisinon by 0
so we gots
if x=0, then we gots a dvision by 0
if we factored out the x and simplified
y=x³-4x

since we factored out the x, thre is a hole at x=0
find the y value
y=x³-4x
y=0³-4(0)
y=0
hole at (0,0)
draw an empty circle arount (0,0)

then we have
y=x³-4x
find roots
y=x(x²-4)
y=x(x-2)(x+2)
roots at x=0,2,-2
wait, 0 is a hole
so put the points (2,0) and (-2,0) on the graph
then subsitute a bunch of points in y=x³-4x
gregori [183]3 years ago
3 0
The only restriction on the domain is that division by zero is undefined, or "not allowed", so x cannot equal zero.

So the domain is x=(-oo,0),(0,+oo)
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Nat2105 [25]

Answer:

1. 5040

2. 20

Step-by-step explanation:

1. using the formula for permutation

nPr=n!/(n-r)!

10P4 = 10!/(10-4)!

=10*9*8*7*6!/6!

then we are left with

=10*9*8*7

=5040

2.using the formula for combination

nCr=n!/(n-r)!r!

6C3=6!/(6-3)!3!

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3 years ago
Please help with this question
never [62]

Answer:

2,744 feet³

Step-by-step explanation:

Volume = Length * Width* Hight

A cube has all the sides equal in measure so Length and Width and Hight are equal and are given in the picture to be 14 feet.

V = 14 *14*14 = 2,744 cubic feet

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3 years ago
Determine the length of the longest metal rod which could be stored in a rectangle box 20 cm by 50 cm by 30 cm.
navik [9.2K]

Answer:

61.64 cm

Step-by-step explanation:

The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:

\therefore \: length \: of \:metal \: rod  \\  =  \sqrt{ {l}^{2} +  {b}^{2}   +  {h}^{2} }  \\  =  \sqrt{ {20}^{2} +  {50}^{2}  +  {30}^{2}  }  \\  =  \sqrt{400 + 2500 + 900}  \\  =  \sqrt{3800}  \\  = 61.64414 \\  = 61.64 \: cm

5 0
3 years ago
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Misha Larkins [42]
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3 years ago
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emmainna [20.7K]

Answer

We have,

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Base area of the pyramid = ?

Assuming height of the pyramid = 20 in

We know that

Volume of pyramid =\dfrac{hlw}{3}  

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           l w = 725.1 in²

Hence, area of the base of the pyramid is equal to 725.1 in².

4 0
3 years ago
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