Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Charlie browns Christmas- 31.25%
How the grinch stole Christmas- 25%
Rudolph the red nosed reindeer- 37.5%
Frosty the snowman- 6.25%
16,310. It's just addition because more than means adding.
Answer:
Explanation:Since, you have not included the formula, I will work here with the formula for
constant accelaration motion that relates the four variables:
displacement (d), Vo (initial velocity), a (acceleration) and t (time).1)
displacement formula:

2) Subtract the term Vot from both sides:

3) Multiply both sides by 2:

4) Divide both sides by t²
![2[d-V_0t]/t^2=a](https://tex.z-dn.net/?f=2%5Bd-V_0t%5D%2Ft%5E2%3Da)
So, you have obtainded:
a = 2[d - Vo×t] / t²Yet, you can arrange it in different ways. For example, you might separate into two terms:
Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:
(km / 3<span>) - 2x = 4
</span>
Adding 2x to both sides:
(km / 3<span>) - 2x + 2x = 4 + 2x
</span>(km / 3<span>) = 4 + 2x
</span>
Subtracting 4 from both sides:
(km / 3<span>) - 4 = 4 + 2x - 4
</span>(km / 3<span>) - 4 = 2x
</span>
Dividing 2 from both sides:
[(km / 3<span>) - 4] /2 = 2x /2
</span>[(km / 3<span>) - 4] /2 = x
</span>x = (km / 6) - 2