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Varvara68 [4.7K]
3 years ago
7

Help and please explain​

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

Negative I think

Step-by-step explanation:

It's going down from left to right, so it's negative I think

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Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
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Complete the square to rewrite the quadratic:

2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5

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... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8

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Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.

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Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In this formula, d is displa
valina [46]
Answer: 

a=2[d-V_0t]/t^2=2d/t^2-2v_0/t

Explanation:


Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).

1) displacement formula:

d= V_0t+\frac{1}{2} at^2

2) Subtract the term Vot from both sides:

d-V_0t= \frac{1}{2} at^2

3) Multiply both sides by 2:

2d -2V_0t=at^2

4) Divide both sides by t²

2[d-V_0t]/t^2=a

So, you have obtainded:

a = 2[d - Vo×t] / t²

Yet, you can arrange it in different ways. For example, you might separate into two terms:

a =  \frac{2d}{t^2} - \frac{2V_0}{t}

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3 years ago
Solve for x.<br><br> 2003-05-04-00-00_files/i0060000.jpg
icang [17]
Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:

(km / 3<span>) - 2x = 4
</span>
Adding 2x to both sides:

(km / 3<span>) - 2x + 2x = 4 + 2x
</span>(km / 3<span>) = 4 + 2x
</span>
Subtracting 4 from both sides:

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Dividing 2 from both sides:

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</span>x = (km / 6) - 2
8 0
3 years ago
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