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3 years ago

Solve for x. 2003-05-04-00-00_files/i0060000.jpg

1 answer:

8 0

Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:

(km / 3) - 2x = 4

Adding 2x to both sides:

(km / 3) - 2x + 2x = 4 + 2x
(km / 3) = 4 + 2x

Subtracting 4 from both sides:

(km / 3) - 4 = 4 + 2x - 4
(km / 3) - 4 = 2x

Dividing 2 from both sides:

[(km / 3) - 4] /2 = 2x /2
[(km / 3) - 4] /2 = x
x = (km / 6) - 2

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How do you do this and what is the answer

Musya8 [376]

Answer:

x = 27

Step-by-step explanation:

The sum of the angles of a triangle is 180.

180 = 105 + 48 + x

x = 180 - (105 +48)

x = 180 - 153

x = 27 degrees

4 0

2 years ago

Read 2 more answers

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Sophie [7]

Answer:

$58 m^{2}$

Step-by-step explanation:

Seperate it into two pieces;

Piece 1, base of 2, height of 9

Piece 2, base of 8, height of 5.

Area of Piece 1:

A = bh

A = 2 (9) = 18

Area of Piece 2:

A = bh

A = 8 (5) = 40

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3 years ago

Which line is perpendicular to y= -3/4x+ 2 if the line passes through the point (3,5)?

iren2701 [21]

Answer:jjdvdudbufh f

Step-by-step explanation:

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3 years ago

Which is defined using the undefined terms point and line

____ [38]

Answer:

It's a ray because it has a point and one line that goes on in a direction.

Step-by-step explanation:

5 0

2 years ago

Angle 0 lies in the second quadrant and sin 0 = 3/5 cos= coy =

Elza [17]

Consider the right triangle ABC with legs AB=4, AC=3 and hypotenuse BC=5. Angle B has
$\sin B=\frac{opposite}{hypotenuse} = \frac{3}{5}$ and
$\cos B = \frac{adjacent}{hypotenuse} = \frac{4}{5}$ .

Since O lies in second quadrant $\cos O\ \textless \ 0$ and
$\cos O= -\cos B =- \frac{4}{5}$ .
Answer: $\cos O=- \frac{4}{5}$ .

3 0

3 years ago