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nydimaria [60]
3 years ago
8

Solve for x. 2003-05-04-00-00_files/i0060000.jpg

Mathematics
1 answer:
icang [17]3 years ago
8 0
Given the equation: (km / 3) - 2x = 4, it is essential to isolate x to obtain the expression to solve it. This is done below:

(km / 3<span>) - 2x = 4
</span>
Adding 2x to both sides:

(km / 3<span>) - 2x + 2x = 4 + 2x
</span>(km / 3<span>) = 4 + 2x
</span>
Subtracting 4 from both sides:

(km / 3<span>) - 4 = 4 + 2x - 4
</span>(km / 3<span>) - 4 = 2x
</span>
Dividing 2 from both sides:

[(km / 3<span>) - 4] /2 = 2x /2
</span>[(km / 3<span>) - 4] /2 = x
</span>x = (km / 6) - 2
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Tobias rented a kayak from a sports equipment store.
Ket [755]

Answer:

B

Step-by-step explanation:

Let x = every day he rented the kayak

Since the store charges $60 for each day, multiply x by 60 like this: 60x

They also have $25 on top of that; 60x + 25

This all has to equal $325; 60x + 25 = 325

To solve for x, subtract 25 from both sides

60x + 25 = 325

       - 25    - 25

60x = 300

Divide both sides by 60

60x/60 = 300/60

x = 5

This means Tobias rented the kayak for 5 days

7 0
2 years ago
Triangle TAG is graphed as shown
solniwko [45]

Answer:

The transformation is (x,y) to (x-2,y-6)

Step-by-step explanation:

First of all, we note the coordinates of the point G

The coordinates of the point G is (2,6)

To bring this to the origin, we are looking at bringing it to the point (0,0)

To do this, we subtract 2 from the x-value and 6 from the y value

So what we have is that;

(x-2) and (y-6)

(x-2, y-6)

4 0
3 years ago
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.
mart [117]

Answer:

  • Decay Problem.
  • Decay rate,  r = 0.014
  • Initial Amount =120,000
  • P(t)=120000(0.986)^t
  • P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

  • Since the population decreases, it is a Decay Problem.
  • Decay rate, r=1.4% =0.014
  • Initial Amount =120,000

Therefore, the function is:

P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t

When t=10 years

P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)

8 0
3 years ago
Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long
Ne4ueva [31]

We are given

Jim's backyard:

Length is

L=15\frac{5}{6} =\frac{95}{6} yards

width is

W=10\frac{2}{5} =\frac{52}{5} yards

Since, this is rectangle

so, we can find area of rectangle

A=L*W

A=(\frac{95}{6})*(\frac{52}{5})

A=\frac{494}{3} yard^2

Area of one sod:

length is

l=1\frac{1}{3} =\frac{4}{3} yards

width is

w=1\frac{1}{3} =\frac{4}{3} yards

Since, it is rectangle in shape

so,

Area=l*w

A=\frac{4}{3}*\frac{4}{3}

A=\frac{16}{9}yard^2

Number of pieces of sod:

we can use formula

Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

N=\frac{\frac{494}{3} }{\frac{16}{9} }

now, we can simplify it

N=\frac{741}{8} pieces need ..............Answer

7 0
3 years ago
Find the sum of the least and greatest two digit prime numbers whose digits are also prime?
adoni [48]
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.

Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.

now we just need to add them for the sum:
23+79=102

hope I helped, and let me know if you have any questions :D
7 0
3 years ago
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