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Free_Kalibri [48]
3 years ago
13

Write the equation of a line with a slope of 3 that passes through (-3,2).

Mathematics
1 answer:
ratelena [41]3 years ago
6 0

Answer:

y = 3x + 11

Step-by-step explanation:

Substitute the information into the point-slope form equation.

Point-slope form: y - y₁ = m(x - x₁)

y - 2 = 3(x - (-3))

y - 2 = 3(x + 3)

y - 2 = 3x + 9

y = 3x + 11

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-1/3(6x+15)-3

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15-2x-8-3x=-x-12+4x+43 Linear Equation
Alex777 [14]

Welcome to Brainly!

Next time, please include the directions.  Here the directions would state, "Solve the following linear equation for x."


15-2x-8-3x=-x-12+4x+43

First:  combine like terms:  15 - 8 - 2x - 3x = 3x + 31 =>  7 - 5x = 3x + 31, or

8x = 24.

Next, solve the above result for x:  x = 24/8 = 3

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6 0
3 years ago
Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu
Svetllana [295]

Answer:

Step-by-step explanation:

Hello!

You have the variable

X: Area that can be painted with a can of spray paint (feet²)

The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²

since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.

a.

P(X>27)

First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of P(Z, you have to do the following conervertion:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

b.

There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².

The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:

X[bar]~N(μ;δ²/n)

So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)

To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.

c.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

d.

No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.

I hope it helps!

4 0
3 years ago
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