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3 years ago

If yard is 3 feet long how many inches are in a yard

1 answer:

7 0

There are 12 inches in a foot and if a yard is 3 feet then do:
3 x 12 and you get 36in
So there are 36 inches in a yard

You might be interested in

Question 1<br> What is the dashed part of the figure below?

Afina-wow [57]

Where is the figure at?

8 0

3 years ago

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Twelve different video games showing violence were observed. The duration times of violence were recorded, with the times (sec

Softa [21]

Answer:

The requirements that must be satisfied are:

- The sample should be reasonably random.

- The sample size should not be higher than 10% of the population.

- The data should not have outliers or excessive skewness.

- The data should be normal or with a sample large enough (usually n>30).

There is no enough information to know if the requirements are satisfied.

Step-by-step explanation:

Ths test hypothesis would be a t-test.

The requirements that must be satisfied are:

- The sample should be reasonably random.

- The sample size should not be higher than 10% of the population.

- The data should not have outliers or excessive skewness.

- The data should be normal or with a sample large enough (usually n>30).

Some conditions are not met, as the sample size (n=12) which is not big enough.

We don't know also if the sample was taken randomly. The size of the sample respect to the population is also unknown.

In conclusion, we can not tell if the requirements are satisfied.

5 0

3 years ago

Micheal has a sink that is shaped like a half-sphere. The sink has a volume of 3000/3π in^3. One day, his sink is clogged. He ha

11Alexandr11 [23.1K]

Answer:

A is 27 i think and B is 15 i think

Step-by-step explanation:

3 0

3 years ago

Write the number thirty five million thirty thousand

Shtirlitz [24]

35,030,000 is the correct answer, hope this helps.

7 0

3 years ago

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6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi

Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of $p = 1 - 0.85 = 0.15$

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

$P = 0.15P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597$

$P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390$

3.90% probability that the third failure will occur on the tenth component tested

5 0

3 years ago