Answer:
I would say the answer is D.
Explanation:
It makes the most sense.
Answer:
D. Population genetics
Population genetics is the study of genetic variation within populations, and involves the examination and modelling of changes in the frequencies of genes and alleles in populations over space and time. ... In natural populations, however, the genetic composition of a population's gene pool may change over time.
Explanation:
microevolution - evolutionary change within a species or small group of organisms, especially over a short period. (Not studying the overall evolution in the population, just a single allele usually) Not it then
macroevolution - Macroevolution in the modern sense is evolution that is guided by selection among interspecific variation, as opposed to selection among intraspecific variation in microevolution (this goes over huge groups of different species) Not it then
gene pool - The gene pool is the set of all genes, or genetic information, in any population, usually of a particular species. (Not the study of evolution in a population) Not that then
So it has to be D
Answer:
The correct answer is - 1:2:1 for black : blue : white chicken.
Explanation:
We know that color of the feather is a trait of the chicken that shows the codominance type of inheritance pattern where both forms of the trait are dominant and make a mix of the forms. In this case, blue is heterozygous BW and black BB and white is WW, then crossed between BW with BW
gametes: B, W and B, W
Punnett
B W
B BB BW
W BW WW
thus, the phenotypic ration is - 1 black : 2 blue : 1 white
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because<u> fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.</u>
<h3>
What is phosphorylation?</h3>
- The crucial process of glycolysis involves the breakdown of glucose into two molecules of pyruvate. It involves a number of steps and many enzymes.
- It takes place over the course of ten phases, demonstrating how important and crucial phosphorylation is to the production of the final goods. Step 1 of the preliminary step (first half of glycolysis) and step 6 of the payout phase reactions are started by phosphorylation (second phase of glycolysis).
- Because fructose-6-phosphate cannot cross the cell membrane, it is forced to remain inside the cell. Step 3 involves phosphorylation, when fructose-6-phosphate is changed into fructose-1,6-bisphosphate.
To learn more about phosphorylation with the given link
brainly.com/question/15585148
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Hello
Gametes are formed after the cell reproduction process mitosis.
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