The standard form equation for a circle is
![(h-x)^2+(k-y)^2=r^2](https://tex.z-dn.net/?f=%28h-x%29%5E2%2B%28k-y%29%5E2%3Dr%5E2)
where (h, k) is the center and r is the radius.
The standard form equation for an ellipse is
![\frac{(x-h)^2}{a^2}} + \frac{(y-k)^2}{b^2} = 1](https://tex.z-dn.net/?f=%5Cfrac%7B%28x-h%29%5E2%7D%7Ba%5E2%7D%7D%20%2B%20%5Cfrac%7B%28y-k%29%5E2%7D%7Bb%5E2%7D%20%3D%201)
(center h, k and major and minor axes a and b)
This equation is standard form for neither, but might be general form for one.
Answer:
b= 9/2
Step-by-step explanation:
4(b-3)=6
(b-3)=6/4
b-3 = 3/2
b = (3/2) + 3
b = (3 + 6)/2
b= 9/2
Let's look at the formula to solve the perimeter.
2l+2w=98
We know that l=6w
Let's put that into the equation.
2(6w)+2w=98
12w+2w=98
14w=98
98÷14=7
So the width is 7. Let's find the length.
Since the length is six times the width: 7×6= 42
So, the length is 42 while the width is 7. We need to find the area.
42×7=294
The area is 294 m².
Tell me if this helps!!