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pogonyaev
3 years ago
13

The area of a rectangle is 6x^3+4x^2−8x. The width of the rectangle is 2x. Find the length of the rectangle.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0

Answer:

1776

Step-by-step explanation:

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Find the slant height of the cone.
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Answer:

The slant height is 13m

Step-by-step explanation:

The slant height of the cone, l , can be found using Pythagoras Theorem.

l^2=12^2+(\frac{10}{2})^2

l^2=12^2+(5)^2

l^2=144+25

l^2=169

l=\sqrt{169}

l=13m

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The answer is B.

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Hurry please <br><br> What is the rule for the reflection?
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Answer:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

Step-by-step explanation:

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Tucker got 80% of the questions correct on his last science test. What fraction of the test questions did he get correct.
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8/10

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The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.
Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

<em>Let X = number of hours spent per week on household chores</em>

So, assuming data follows normal distribution; X ~ N(\mu=28,\sigma^{2}=7^{2})

The z score probability distribution for sample mean is given by;

               Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean hours = 28

            \sigma = standard deviation = 7 hours

            n = sample of adults = 49

<em>Let </em>\bar X<em> = sample mean hours spent per week on household chores</em>

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P(\bar X > 26.75 hours)

    P(\bar X > 26.75 hours) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{26.75-28}{\frac{7}{\sqrt{49} } } ) = P(Z > -1.25) = P(Z < 1.25)

                                                                     = 0.89435  {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

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3 years ago
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