Answer:
Step-by-step explanation:
The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines
Slope of line 1:
(Yb -Ya)/(Xb - Xa) =
(-10 - (-14))/(-1 - (-3)) =
4/2 =
2
Use that slope to find the Y-intercept of line 1
y = 2x + b
-14 = 2(-3) +b
-14 = -6 + b
-8 = b
Therefore Line 1 is:
y = 2x - 8
Slope of line 2
(11 - 13)/(-1 - (-3)) =
-2/2 =
-1
Y-intercept of line 2
y = -x + b
13 = -(-3) +b
13 = 3 + b
10 = b
Therefore line 2 is
y = -x + 10
Now we have 2 equations to solve for the coordinates x and y
y = 2x - 8
y = -x + 10
Substitute y out in one of the equations
2x - 8 = -x + 10
3x = 18
x = 6
Plug x into one of the equations
y = 2(6) - 8
y = 12 - 8
y = 4
Therefore the solution is:
x=6, y=4
Answer:
The two that are blank are 2 and 7
Step-by-step explanation:
Answer:
When x = -2, y = 3
When x = -1, y = 0
When x = 0, y = -3
When x = 1, y = -6
Step-by-step explanation:
Given:
y = -3x - 3
Fill in the table using the following value for x
When x = -2
y = -3x - 3
y = -3(-2) - 3
y = 6 - 3
y = 3
When x = -2, y = 3
When x = -1
y = -3x - 3
y = -3(-1) - 3
y = 3 - 3
y = 0
When x = -1, y = 0
When x = 0
y = -3x - 3
y = -3(0) - 3
y = 0 - 3
y = -3
When x = 0, y = -3
When x = 1
y = -3x - 3
y = -3(1) - 3
y = -3 - 3
y = -6
When x = 1, y = -6
Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To find b, you first need to calculate slope and see where the line intersects the y-axis.
To get m (slope), use the form y1 - y2/x1 - x2. It would look like this:
2 - 12/-1 - 4. This simplifies to:
-10/-5, which further simplifies to 2. Now, graph the points to find y....
My graph shows that the line intersects at (0, 4), so slope-intercept form would look like:
y = 2x + 4 (remember, 2 is the slope and 4 is the y-intercept)
Hope this helps.
